Answer:
0.897 J/g°C
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass (M) of substance = 155g
Initial temperature (T1) = 25.0°C
Final temperature (T2) = 40°C
Change is temperature (ΔT) = T2 – T1 = 40°C – 25.0°C = 15°C
Heat Absorbed (Q) = 2085 J
Specific heat capacity (C) of the substance =?
Step 2:
Determination of the specify heat capacity of the substance.
Applying the equation: Q = MCΔT, the specific heat capacity of the substance can be obtained as follow:
Q = MCΔT
C = Q/MΔT
C = 2085 / (155 x 15)
C = 0.897 J/g°C
Therefore, the specific heat capacity of the substance is 0.897 J/g°C
