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Ierofanga [76]
3 years ago
14

Which of the following phrases describes a motor?

Physics
1 answer:
Delicious77 [7]3 years ago
7 0
Your answer is d I believe
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what is the kinetic energy of an object that as a mass of 12 kilograms and moves with the velocity of 10 m/s
Galina-37 [17]

Answer:

120 m/s

Explanation: QUIZLET

7 0
3 years ago
A projectile is launched upward at an angle of 70⁰ from the horizontal and strikes the ground a certain distance down range. For
OLga [1]

Answer:20°

Explanation:

Recall

Range R of a projectile is given by U^2sin2A/g

We're U = velocity,A= angle of projection and g is acceleration due to gravity

From the question the range R are the same

Hence R1=R2

U1^2sin2A/g=U2^2sin2B/g

But U1=U2 and g=g

Hence sin2A=sin 2B

Sin 2*70= sin2*B

0.6427=sin2B

B=sin inverse(0.6427)=40/2=20°

7 0
3 years ago
A man pushing a crate of mass
marin [14]

(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.

(b) The net work done on the crate while it is on the rough surface is 23.7 J.

(c) The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.

<h3>Magnitude of net force on the crate</h3>

F(net) = F - μFf

F(net) = 280 - 0.351(92 x 9.8)

F(net) = -36.46 N

<h3>Net work done on the crate</h3>

W = F(net) x L

W = -36.46 x 0.65

W = - 23.7 J

<h3>Acceleration of the crate</h3>

a = F(net)/m

a = -36.46/92

a = - 0.396 m/s²

<h3>Speed of the crate</h3>

v² = u² + 2as

v² = 0.845² + 2(-0.396)(0.65)

v² = 0.199

v = √0.199

v = 0.45 m/s

Thus, the magnitude and direction of the net force on the crate while it is on the rough surface is 36.46 N, opposite as the motion of the crate.

The net work done on the crate while it is on the rough surface is 23.7 J.

The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

7 0
2 years ago
Two linear polarizing filters are placed one behind the other so that their transmission directions form an angle of 45 ° . A be
makvit [3.9K]

The transmitted intensity will be the quarter of the incident intensity of light, (I = 0.25 I₀), when two linear polarizing filters are placed one behind the other forming the angle of 45°.

<u>Explanation:</u>

Polarizers are used for constraining the direction of propagation of light waves.  So depending upon the angle of polarizer, the transmitted rays will follow that angle only and the remaining lights waves at different angles will be reflected back. So basically it works like a filter or optical filters.

So, the transmitted intensity will be less compared to the original intensity of light as the beam will get confined in a particular angle.

The relation between transmitted intensity and incident intensity is given by Malus's law.

I = { \frac {I_{0}} {2}} \times cos^{2} \alpha

Here, I is the transmitted intensity, I₀ is the incident intensity and α is the angle of the polarizer.

In the present case, two polarizers are used with same angle, so the first one termed as polarizer, while the second one will be termed as analyzer. The angle which is used to polarize the intensity of the incident beam is the angle of 45°.

Then, according to Malus's law,

I = I₀ cos² 45 = (I₀/2)×(1/√2)² = I₀/4 = 0.25\ I_0

So, the transmitted intensity will be the quarter of the incident intensity of light, (I = 0.25 I₀), when two linear polarizing filters are placed one behind the other forming the angle of 45°.

6 0
3 years ago
Physic pressure chapter
nexus9112 [7]
I thing its d.) if i am wrong sorry ) iam from different county so )
7 0
3 years ago
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