1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sladkih [1.3K]
3 years ago
15

Which expressions have an estimated quotient of 200? Select all that apply.

Mathematics
1 answer:
marta [7]3 years ago
3 0

Answer:

E

                                       

                                             

Hope it helps!                    

You might be interested in
What is the area of the polygon ?
Effectus [21]

Answer:

C)  99 in²

Step-by-step explanation:

you can divide this shape by drawing a horizontal line to create a 4x12" rectangle and a trapezoid with a height of (10-4) in and bases of 12 and 5"

area of rectangle:  12 x 4 = 48

area of trapezoid:  1/2(6)(12+5) = 3(17) = 51

total area = 48 + 51

total area = 99 in²

7 0
2 years ago
Read 2 more answers
A family built a house and wanted to put down in their rectangular yard. The sod costs $0.32 per square foot plus 10 per square
sammy [17]

Answer:

The total cost of purchasing and laying sods in the rectangular yard is $2,146.67  

Step-by-step explanation:

We are given the following in the question:

Dimensions of rectangular yard:

Length = 50 feet

Width = 30 feet

Area of rectangular yard =

A = \text{Length}\times \text{Width}\\A = 50\times 30\\A  = 1500\text{ square feet}

Cost of sod = $0.32 per square foot

Total cost of sod =

C_1 = \text{Unit cost of sod}\times \text{Area of yard}\\C_1 = 0.32\times 1500\\C_1 = 480\$

Cost of laying sods = $10 per square yard

Total cost of laying sod =

C_2 = \text{Unit cost of laying sod}\times \text{Area of yard}\\\\\text{1 square yard}=\dfrac{1}{9}\text{Square foot}\\\\C_2 = 10\times \dfrac{1500}{9}\\\\C_2 = 1666.67\$

Total cost of purchasing and laying the sod =

C = C_1 + C_2\\C = 480 +1666.67\\C = \$2,146.67

Thus, the total cost of purchasing and laying sods in the rectangular yard is $2,146.67

3 0
3 years ago
The area of a rectangle is 168 square feet. The ratio of the width to the length is
nlexa [21]

Answer:

Width = 12 feet

Step-by-step explanation:

Given that,

Area of a rectangle is 168 square feet.

The ratio of the width to the length is  6:7.

Let the length is 7x and width is 6x.

According to question,

Area = 168 sq feet

l×b=168 sq feet

7x × 6x = 168

42x² = 168

x² = 4

x = 2

Length = 7x = 7(2) = 14 feet

Breadth = 6x = 6(2) = 12 feet

So, the width of the rectangle us 12 feet.

5 0
2 years ago
A washer and a dryer cost $862
Svetlanka [38]

The cost of dryer is $450 and the cost of washer is $412

4 0
3 years ago
Point A is located at (-2, -6) and is translated 4 units up. What are the coordinates of point A'?
gavmur [86]
Its A because the vertical line is the y-axis so 4+-6 is -2 and the x-axis would remain the same. <span>#TeamAlvaxic</span>
5 0
3 years ago
Other questions:
  • Rectangle with area of 10 and length of 2 1/2. Whats the width?
    9·2 answers
  • 1. Dennis started hiking at sea level. He recorded his starting position as 0. He climbed upward,
    14·1 answer
  • 50 POINTS PLUS BRAINLIEST!
    14·1 answer
  • Graph g(t)=4sin(3t)+2
    9·1 answer
  • Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed 4/17 cups from the first or
    14·1 answer
  • What is the slope of the line that passes through (-7, 8) and (9, -4)?<br> Help plz
    8·2 answers
  • Need help with 2 and 4 ASAP <br> Inverses...
    12·1 answer
  • The graph below has the same shape as the graph of G(x) = x, but it is
    7·1 answer
  • A Jorge le otorgaron una beca de $60.000 por sus buenas calificaciones y escasos recursos. Si gasta cada me la 2\5 partes de la
    14·1 answer
  • Evaluate sequences in recursive form <br><br> g(1) = 4<br> { g(2) = -3<br> g(n)=g(n-2)•g(n-1)
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!