What do you need help with?
Answer:
a. 0.0081
b. 1.167
Step-by-step explanation:
Please see attachment, the yellow colour are emphasies to be noted
The <span>line determined by ( -4 , 3 ) and ( 6 , 3 ) has the slope
3-3
m = ------- = 0.
10
Normally the slope of a line perpendicular to one with slope m is the negative reciprocal of m. Here, however, the slope is zero, and the negative reciprocal of that does not exist. This signifies a VERTICAL line with undefined slope.
Thus, all we have to do to locate this line is to look at the x component of the given point thru which the line is to pass: That comp is 2.
Thus, the equation of the new line perpendicular to the old is x = 2.</span>
Answer:
Step-by-step explanation:
You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.
You will find when you look on your trig identity sheet that
so we will make that replacement, getting everything in terms of sin:
Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:
We can factor out the sin(theta), since it's common in both terms:
Because of the Zero Product Property, either
or
Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:
The next equation needs to first be solved for sin(theta):
so
and
Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are: