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Arada [10]
3 years ago
9

B. (x – 3)2 – 4(x - 2)(x + 2) - 10

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

it's true it is b

Step-by-step explanation:

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She has $60. After buying 5 hair clips,she had $30 left. How much did each hair clip including tax
mixas84 [53]
60-5h=30  subtract 60 from both sides

-5h=-30  divide both sides by -5

h=6

So each hair clip cost $6.00
3 0
4 years ago
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This number is in scientific notation. 2. 4 × 10-4 Convert the number into standard notation. What is the value? 2. 4 × 10-4 =.
Dimas [21]
2.4x10^-4 = 0.00024
7 0
2 years ago
The movie started at 6:32 p.m. and ended at 9:48 p.m. How long did the movie last?
lapo4ka [179]
First, add hours until the difference is less than an hour. You can add 3 hours on to make it 9:32 p.m. Then, add minutes on until it's the exact time. from 9:32 to 9:48, you can add 16 minutes, so the total time in the movie was 3 hours, 16 minutes.
7 0
3 years ago
I need help to solve this and also Hearn will the bacteria be over 100,000
lapo4ka [179]

Hello! Let's look at the two parts of this question.

Complete the table:

In this case, you just substitute the value of "hour" into the equation, for the value of t. For example:

P(0) = 120 (2)^{0}

P(0) = 120 (1)

P(0) = 120

Therefore, the number of bacteria for hour 0 is 120.

You can do this for the next ones. Hour 1 = 240, hour 2 = 480, and so on. (In this case, you can keep multiplying by 2)

Estimate when there will be more than 100,000 bacteria:

Set the final value of P(t) = 100,000, then solve.

100,000 = 120 (2)^{t}

833.33 = (2)^{t}

t = log_{2}833.33

t = 9.702744108

So your answer would be around 9.7 years, or, around 10 years.

Hope this helps!

3 0
3 years ago
A thread is wound 200 times round a reel of diameter 5 cm. Use the value 3 for it to find the approximate length of the thread i
Radda [10]

Answer:

Length of the thread = 30 metres

Step-by-step explanation:

Length of the thread in one round of a reel = Circumference of the reel

                                                                    C = 2\pi r

Since radius of the reel = \frac{\text{Diameter}}{2}

                                       = \frac{5}{2}

                                       = 2.5 cm

Circumference of the reel = 2(π)(2.5)

                                           = 5π

                                           = 5×3

                                           = 15 cm

Length of the thread wound in one round around the reel = 15 cm

Since, thread is wound 200 times round a reel, length of the thread

= 200 × 15                                                      

= 3000 cm

≈ 30 metres

Therefore, Option (B) will be the answer.

0 0
3 years ago
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