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I am Lyosha [343]
3 years ago
13

Find the value of c so that (x-5) is a factor of the polynomial p(x)

Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

I think the question is

Find the value of c so that (x-5) is a factor of the polynomial

p(x) = x^3 + 2x^2 + cx + 10

The other factor is going to be some quadratic.  We can say a few things about its coefficients but let's start by saying in general it's

q(x)= ax^2 + bx + k

p(x) = (x-5)q(x)

x^3 + 2x^2 + cx + 10 = (x-5)(ax^2 + bx+k) = ax^3 + (b-5a)x^2 + (k-5b)x - 5k

Equating respective coefficients,

a=1

b-5a = 2

k - 5b = c

-5k = 10

so we get

b = 2 + 5 = 7

k = 10/-5 = -2

c = k - 5b = 2 - 5(7)= -37

Answer: -37

Check:

(x^2 + 7x - 2)(x - 5) = x^3 + 2 x^2 - 37 x + 10\quad\checkmark




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