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BartSMP [9]
3 years ago
9

The reaction of 9.50 g of carbon with Excess O2 Yield 12.8 of CO2. What is the percent yield of this reaction?

Chemistry
1 answer:
Anna [14]3 years ago
5 0

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

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To get the molar mass, you will need to first determine the atoms in the compound.

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Next step is to determine how many atoms of each element you have in the compound. The subscript will tell you how many. If you see no subscript, that means 1 atom.

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Then you multiply the number of atoms by the atomic weight to get the molar mass of each element and add them up to get the total molar mass of the compound:

Element          # of atoms        atomic weight           molar mass

Al                         1               x     26.98 g/mole =    26.98 g/mole

Cl                         3              x     35.45 g/mole =   <u>106.35 g/mole</u>

                                                             TOTAL =   133.33 g/mole

8 0
3 years ago
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(b) There may be some experimental errors like:

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