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2 years ago

A car traveling initially at 7.35 m/s acceler-

Physics

1 answer:

Flura [38]2 years ago

4 0

Answer:

$v_f=9,07~m/s$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

The car initially travels at vo=7.35 m/s and accelerates at a rate of $a=0.824~m/s^2$ during t=2.09 s.

The final velocity is:

$v_f=7.35+0.824*2.09$

$\mathbf{v_f=9,07~m/s}$

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From the edge of a cliff, a 0.46 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up

wel

Answer:

Explanation:

Given

mass of Projectile(m)=0.46 kg

Initial Kinetic Energy=1430 J

Maximum upward displacement from Launch point=150 m

$K.E.=\frac{mv^2}{2}$

$1430\times 2=0.46\times v^2$

v=78.85 m/s

and $H_{max}=\frac{v^2\sin ^2\theta }{2g}$

$150=\frac{(78.85)^2\sin ^2\theta }{2\times 9.8}$

$\sin \theta =0.687$

$\theta =43.39^{\circ}$

initial horizontal velocity $(v_x)=v\cos \theta$

$v_x=78.84\times \cos (43.39)=57.29 m/s$

Initial vertical velocity $(v_y)=v\sin \theta$

$v_y=78.85\times \sin (43.39)$

$v_y=54.16 m/s$

(c)vertical velocity at any instant=65 m/s

Since initial vertical velocity is 54.16 m/s

so 65 m/s will be acquired when projectile started falling below cliff

$v^2-u^2=2 a s$

$65^2-54.16^2=2\times 9.8\times s$

$s=65.90 m$

7 0

2 years ago

What energy powers the star throughout its life?

aleksley [76]

<span>It is called Nuclear fusion. Stars are controlled by atomic combination in their centers, generally changing over hydrogen into helium. The generation of new components by means of atomic responses is called nucleosynthesis. A star's mass figures out what another kind of nucleosynthesis happens in its center.</span>

3 0

3 years ago

The following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2,

katen-ka-za [31]

(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.

(b) The velocity and acceleration at any time t is v = (4ti + j) m/s and a = a = 4i m/s²

<h3>Position of the particle</h3>

x = at²i + btj

x = 2t²i + tj

<h3>Average velocity, at t₁=2sec and t₂=3sec</h3>

Δv = Δx/Δt

x(2) = 2(2)²i + 2j

x(2) = 8i + 2j

|x(2)| = √(8² + 2²) = 8.246

x(3) = 2(3)²i + 3j

x(3) = 18i + 3j

|x(3)| = √(18² + 3²) = 18.248

Δv = (18.248 - 8.246)/(3 - 2)

Δv = 10 m/s

<h3>Velocity and acceleration at any time, t</h3>

v = dx/dt

v = (4ti + j) m/s

a = dv/dt

a = 4i m/s²

<h3>Average acceleration</h3>

v(2) = 4(2)i + j

v(2) = 8i + j

|v(2)| = 8.06 m/s

v(3) = 4(3)i + j

v(3) = 12i + j

|v(3)| = 12.04 m/s

a = (12.04 - 8.06)/(3 - 2)

a = 3.98 m/s²

Learn more about average acceleration here: brainly.com/question/104491

#SPJ1

6 0

2 years ago

According to Newton’s law of universal gravitation, as the mass or one or both bodies increases, what happens to the force of at

wel

Answer:

force increases

Explanation:

Newton's law of universal gravitation states that the force of attraction (gravity) acting between the Earth and all physical objects is directly proportional to the Earth's mass, directly proportional to the physical object's mass and inversely proportional to the square of the distance separating the Earth's center and that physical object.

According to Newton’s law of universal gravitation, as the mass or one or both bodies increases, the force of attraction between the bodies increases.

Mathematically, this is given by the Newton's Second Law of Motion;

Force = mass * acceleration.

3 0

3 years ago

If an object has a density of .9g/ml and a volume of 12ml what is the mass of the object

BaLLatris [955]

Answer: 10.8 g

Explanation: Density = mass/ volume

So, Mass = density * volume = 0.9 g/ml * 12 ml = 10.8g

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2 years ago