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3 years ago

A car traveling initially at 7.35 m/s acceler-

Physics

1 answer:

Flura [38]3 years ago

4 0

Answer:

$v_f=9,07~m/s$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

The car initially travels at vo=7.35 m/s and accelerates at a rate of $a=0.824~m/s^2$ during t=2.09 s.

The final velocity is:

$v_f=7.35+0.824*2.09$

$\mathbf{v_f=9,07~m/s}$

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A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he

frez [133]

Answer:

$\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}$

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

$a=\frac{v_f-v_i}{t}$

The final velocity is 3 meters per second. The initial velocity is 8 meters per second.

We need to convert the time to seconds.

t= 1 minute
60 seconds = 1 minute
t=60 seconds

So, we know that:

$v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s$

Substitute the values into the formula.

$a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}$

Solve the numerator.

3 m/s - 8 m/s = -5 m/s

$a=\frac{-5 \ m/s}{60 \ s}$

Divide.

$a=-0.0833333333 \ m/s/s$

Let's round to the nearest hundredth.

The 3 in the thousandth place tells us to leave the 8 in the hundredth place.

$a\approx -0.08 \ m/s^2$

The cyclist's acceleration is about $\boxed {-0.08 m/s^2}$

8 0

3 years ago

Light is an example of a mechanical wave in nature? true or false

Zina [86]

Answer:

The answer is False.

Explanation:

The Light is a form of energy ( known as luminous energy ) that can be perceived by the human eye, therefore it allows us to see what surrounds us. Light is an electromagnetic radiation that spreads in the form of spherical waves in any space, consequently, it is not a mechanical wave.

5 0

4 years ago

Read 2 more answers

Assume that the pressure in a room remains constant at 1.01

Ray Of Light [21]

Answer:

Explanation:

Given

Pressure $P_1=1.01\times 10^5 Pa$

Volume of air $V=60 m^3$

Initial Temperature $T_1=289 K$

$T_2=302 K$

Initial moles is given by

$PV=nRT$

$n_1=\frac{P_1V_1}{RT_1}$

$n_1=\frac{1.01\times 10^5\times 60}{R\cdot 289}$

when some gas escape out

no of moles is equal to

$n_2=\frac{P_2\times V_2}{R\cdot T_2}$

$n_2=\frac{1.01\times 10^5\times 60}{R\cdot 302}$

remaining no of moles $=n_1-n_2$

$=\frac{1.01\times 10^5\times 60}{R\cdot 289}-\frac{1.01\times 10^5\times 60}{R\cdot 302}$

$=\frac{1.01\times 10^5\times 60}{R}(\frac{1}{289}-\frac{1}{302})$

Mass of air escape out

$=(n_1-n_2)\times M$

$=(\frac{1.01\times 10^5\times 60}{R}(\frac{1}{289}-\frac{1}{302}))\times 28$

$=25.272\times 10^3\ g$

$m=25.272\ kg$

7 0

4 years ago

What is the force of impact of a 100 kg diver who falls into a swimming pool and hits the surface of the water and comes to a st

Simora [160]

Answer:

F = 53153.36[N]

Explanation:

In order to solve this problem, we must first use the principle of conservation of energy which is transformed from potential energy to kinetic, in this way we can determine the velocity at which the person enters the water.

$E_{pot}=E_{kin}\\m*g*h=\frac{1}{2}*m*v^{2}$

where:

m = mass = 100 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 9 [m]

v = velocity [m/s]

Now replacing we can determinate the velocity.

$v^{2}=2*g*h\\v=\sqrt{2*g*h}\\v=\sqrt{2*9.81*9}\\v = 13.28[m/s]$

Then we can calculate the momentum which can be calculated as the product of force by time, this momentum is also equal to the product of mass by velocity.

$P=m*v\\and\\P =F*t\\F*t=m*v$