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2 years ago

A car traveling initially at 7.35 m/s acceler-

Physics

1 answer:

Flura [38]2 years ago

4 0

Answer:

$v_f=9,07~m/s$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

The car initially travels at vo=7.35 m/s and accelerates at a rate of $a=0.824~m/s^2$ during t=2.09 s.

The final velocity is:

$v_f=7.35+0.824*2.09$

$\mathbf{v_f=9,07~m/s}$

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Answer:

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Answer:

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