All categories

2 years ago

A car traveling initially at 7.35 m/s acceler-

Physics

1 answer:

Flura [38]2 years ago

4 0

Answer:

$v_f=9,07~m/s$

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes uniformly in time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

The car initially travels at vo=7.35 m/s and accelerates at a rate of $a=0.824~m/s^2$ during t=2.09 s.

The final velocity is:

$v_f=7.35+0.824*2.09$

$\mathbf{v_f=9,07~m/s}$

You might be interested in

The ability to adjust to an artificially displaced or even inverted visual field is called

egoroff_w [7]

Answer:

méthode if séparation muddy water

3 0

2 years ago

What are two reasons why density is a useful physical property for identifying substances?

padilas [110]

Some substances look alike and the density can help you determine which is which. It also helps to tell which is heavier than the other.

4 0

3 years ago

Plz, help me! I will give brainliest

Viktor [21]

It’s A liquid to a solid because if it’s a liquid they can move but not much and then it becomes a solid because they are packed closely together and are fixed in one position.

3 0

3 years ago

Read 2 more answers

A tensile test specimen has a gage length = 50 mm and its cross-sectional area = 100 mm2. The specimen yields at 48,000 N, and t

Shalnov [3]

Answer:

a) yield strength

$\sigma_y = \dfrac{F_y}{A} = =\dfrac{48000}{100} = 480 MPa$

b) modulus of elasticity

strain calculation

$\varepsilon_0=\dfrac{L-L_0}{L_0}=\dfrac{50.23-50}{50} = 0.0046$

strain for offset yield point

$\varepsilon_{new} = \varepsilon_0 -0.002$

=0.0046-0.002 = 0.0026

now, modulus of elasticity

$E = \dfrac{\sigma_y}{\varepsilon_{new}}=\dfrac{480}{0.0026}$

= 184615.28 MPa = 184.615 GPa

c) tensile strength

$\sigma_u =\dfrac{F_{max}}{A}=\dfrac{87000}{100}=870MPa$

d) percentage elongation

$\% Elongation = \dfrac{L-L_0}{L_0}\times 100 = \dfrac{67.3-50}{50}\times 100 = 34.6\%$

e) percentage of area reduction

$\% Area\ reduction = \dfrac{A-A_f}{A}\times 100=\dfrac{100-53}{100}= 47 \%$

7 0

3 years ago

Directions: Fill in the blank with the correct word. Choose from the list of possible answers in the word bank below:

Alexxx [7]

Answer:

1).atoms (3). mixture. (5). Element

2). particles (4). molecules (6). suspension

Explanation:

(7). Homogeneous (8). Heterogeneous

(9). compound (10). solutions

8 0

3 years ago