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Lostsunrise [7]
3 years ago
8

Indicate the result of each of the following unit vector cross products (unit vector hat-symbols not shown): . kxi = . jxi= -jxk

= • ixi = • ur Xue =
Physics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

Explanation:

The cross product of two vectors is given by

\overrightarrow{A}\times \overrightarrow{B}=\left | \overrightarrow{A} \right |\left | \overrightarrow{B} \right |Sin\theta \widehat{n}

Where, θ be the angle between the two vectors and \widehat{n} be the unit vector along the direction of cross product of two vectors.

Here, K x i = - j

As K is the unit vector along Z axis, i is the unit vector along X axis and j be the unit vector along  axis.

The direction of cross product of two vectors is given by the right hand palm rule.

So, k x i = j

j x i = - k

- j x k = - i

i x i = 0

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Convert 23 miles into feet.<br> **There are 5280 feet in 1 mile** *
zhenek [66]

Answer:

121440 feet is 23 miles.

5280 x 23= 121440

To check your answer just divide 121440 by 5280, which gives you 23.

Hopefully this helps you!

8 0
3 years ago
Which statements describe the image produced by a concave lens?check all that apply.
kotegsom [21]

<em>Answer:</em>

<em>The answers are: </em>

  • <em>A-which is the image is always right side up.</em>
  • <em>E-the image is virtual</em>

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7 0
4 years ago
Read 2 more answers
Which identifies a machine that converts mechanical energy into electrical energy?
yKpoI14uk [10]
The answer is the option c. generator. Generator is a machine that converts mechanical energy into electricity. The way it is made is because the mechanical movement may be transformed in rotation of magnets placed inside a coiled wire, and this induces the movement of electrons through the coiled wire. As you know electricity is the flow of electrons.
8 0
3 years ago
A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?
Ad libitum [116K]
Diameter = 0.170 meter
Circumference = 0.170 π meters

530 rpm = 530 circumferences / minute

               =  (530 x 0.170 π meters) / minute

               =      283.06 meter.minute

               =        4.72 meters/second
8 0
3 years ago
A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____
Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}, f = focal length of the mirror

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}

v = -8.57 cm

The magnification of a mirror is given by,

m=\dfrac{-v}{u}

m=\dfrac{-(-8.57)}{-20}

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

5 0
4 years ago
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