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iris [78.8K]
3 years ago
14

How many 100W light bulbs could be powered for one year by the direct conversion of 1g of matter into energy?

Physics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

No. of 100 W bulbs, n = 28,539 bulbs

Given:

Power of a single bulb = 100 W

Time period, T = 1 yr = 365\times 24\times 60\times 60 = 31,536,000 s

mass of matter, m = 1 g = 1\times 10^{-3}]

Solution:

According to Eintein's mass-energy equivalence:

E = mc^{2}

E = 1\times 10^{-3}\times (3\times 10^{8})^{2}

E =  9\times 10^{13} J

Power of a single bulb, P =  \frac{E}{T}

                                       P =  \frac{9\times 10^{13} }{31,536,000}

                                       P = 28,53,881 W

No. of 100 W bulbs, n = \frac{P}{power of one bulb}

                                 n = \frac{28,53,881}{100}

                                 n = 28,539

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A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors
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Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, F_1 = 140 N

let the second force = F_2

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N

F_2 = 280 \ East

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N

F_2 = 560 \ West

8 0
3 years ago
A current of 2.0A flows through a light bulb. What is the amount of charge flowing through the light bulb in 40 seconds?
lidiya [134]

Answer:

Quantity of charge = 80 Coulombs

Explanation:

Given the following data;

Current = 2 A

Time = 40 seconds

To find the amount of charge flowing through the light bulb;

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Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 2 * 40

Quantity of charge = 80 Coulombs

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2 years ago
The force that accelerates a rocket in outer space is exerted on the rocket by the?
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3 0
1 year ago
a 5 charge is locataed 1.25 m to the left of a -3 charge. What is the magnitude and direction of the electrostatic force on the
Alika [10]

Answer:

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Explanation:

The electrostatic force on the charges is given by Coulomb's law;

F= Kq1q2/r^2

This an inverse square law.

F= electrostatic force on the charges

K= constant of Coulomb's law

q1 and q2= magnitude of the charges

Since K= 9.0×10^9Nm^2C^2

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The force is 86.5×10^9 N towards the negative charge.

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2 years ago
A car is moving at a velocity of 25 ms-1.
lianna [129]
Velocity = 25 + (6x3)= 43 m/s
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