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3 years ago

A single atom of platinum has a mass of 3.25 x 10-22g. What is the mass of 6.0 x 1023 platinum atoms?

1 answer:

6 0

Even though the numbers are in scientific notation, they are still just numbers. Essentially the question is as simple as "An apple weighs an ounce, how much do 35 apples weigh?". So all you have to do is multiply.

3.25 x $10^{-22}$ x 6.0 x $10^{23}$ = 195

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PAP Physical Studies<br><br> How can you remember the periodic table?

siniylev [52]

Break down the table into smaller sections. Memories period by period or if you like by group (like halogens or noble gases).
Just say the elements in order everyday 1-10 then when you get those 11-20 and continued.

3 0

3 years ago

Read 2 more answers

Burka [1]

Answer:

$\large \boxed{\text{E) 721 K; B) 86.7 g}}$

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL; V₂ = 435 mL

T₁ = 355 K; T₂ = ?

b) Calculation

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}$

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

$\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}$

7 0

3 years ago

The ease which an acid or base dissociates in a solution refers to

Andrew [12]

Answer:

c.) saturation

Explanation:

5 0

3 years ago

How many moles of N2 are in a flask with a volume of 0.5 L at a pressure of 400.0 kPa and a temperature of 300.0 K?

mylen [45]

Answer:

0.08moles

Explanation:

Given parameters:

Volume of gas = 0.5L

Pressure of gas = 400kPa

Temperature of gas = 300K

Unknown:

Number of moles of N₂ = ?

Solution:

Applying the ideal gas law which is a combination of the three gas law: Boyle's law, Charles's law and Avogadro's law will solve this problem.

The ideal gas law is stated as;

PV = nRT

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature of the gas

We need to convert kPa of the pressure to atm which is a more comfortable unit to work with.

400kPa will be $\frac{400}{101.325}$ = 3.95atm

Input the variables in the equation;

3.95 x 0.5 = n x 0.082 x 300

n = 0.08moles

5 0

3 years ago

Indicate whether fluorine of bromine has larger value

tensa zangetsu [6.8K]

Bromine has larger ionic radius and atomic radius than fluorine.

Fluorine has larger ionisation energy and electronegativity than bromine.

<h3>What are halogen?</h3>

Halogen are those elements that are found in group 7 of the periodic table.

Fluorine is in period two of the periodic table, meaning that it contains electrons in only the first two energy levels at ground state. It has a higher ionization energy and electronegativity than bromine.

Learn more about ionic radius here:

brainly.com/question/8137711

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Indicate whether fluorine or bromine has a larger value for each of the following properties. a. electronegativity b. ionic radius c. atomic radius d. ionization energy

7 0

2 years ago