Answer:double displacement
Explanation:I just did it
Answer is: the specific heat capacity of the metal is <span>A) 0.129 J/gK.
</span>m(metal) = 15,1 g.
Q = 48,75 J.
ΔT = 25 K.
Q = C · ΔT · m(metal).
C = Q ÷ ΔT · m(metal).
C = 48,75 J ÷ 25 K · 15,1 g.
C = 0,129 J/g·K.
Given molecule Lithium iodide (LiI)
Heat of hydration = -793 kj/mol
Lattice energy = -730 kJ/mol
Heat of hydration = Heat of solution - Lattice energy
Heat of solution = Hydration + Lattice = -793 + (- 730) = -1523 kJ/mol
Now,
Mass of LiI = 15.0 g
molar mass of LiI = 134 g/mol
# moles of LiI = 15/134 = 0.112 moles
Heat of solution for 1 mole of LiI = -1523 KJ
Therefore, for 0.112 moles of LiI the corresponding heat is
= 0.112 *(-1532) = 171.6 kJ
Answer:
the load is between the fulcrum and the handle
Explanation:
