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liq [111]
3 years ago
10

Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. Given 96.1 grams of calcium nitrate,

what’s the theoretical yield of calcium phosphate? Use the periodic table and the polyatomic ion resource.
The mass of calcium phosphate the reaction can produce is blank

grams.
Chemistry
2 answers:
jek_recluse [69]3 years ago
4 0

Answer:

99.56 g.

Explanation:

  • The balanced reaction is:

<em>3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂.</em>

It is clear that 3.0 moles of Ca(NO₃)₂ react with 2.0 moles of Na₃PO₄ to produce 6.0 moles of NaNO₃ and 1.0  mole of Ca₃(PO₄)₂.

  • We need to calculate the no. of moles of 96.1 g of Ca(NO₃)₂:

n = mass/molar mass = (96.1 g)/(164.088 g/mol) = 0.5857 mol.

<u><em>Using cross multiplication:</em></u>

3.0 moles of Ca(NO₃)₂ produce → 6.0 moles of NaNO₃.

0.5857 moles of Ca(NO₃)₂ produce → ??? moles of NaNO₃.

∴ The no. of moles of NaNO₃ = (6.0 mol)(0.5857 mol)/(3.0 moles) = 1.171 mol.

<em>∴ The no. of grams of NaNO₃ = (no. of moles of NaNO₃)(molar mass)</em> = (1.171 mol)(84.99 g/mol) = <em>99.56 g.</em>

Svet_ta [14]3 years ago
3 0

Answer: The mass of calcium phosphate will be, 61.07 grams

Explanation : Given,

Mass of calcium nitrate = 96.1 g

Molar mass of calcium nitrate = 164 g/mole

Molar mass of calcium phosphate = 310 g/mole

First we have to calculate the moles of calcium nitrate.

\text{Moles of }Ca(NO_3)_2=\frac{\text{Mass of }Ca(NO_3)_2}{\text{Molar mass of }Ca(NO_3)_2}=\frac{96.1g}{164g/mole}=0.59moles

Now we have to calculate the moles of calcium phosphate.

The balanced chemical reaction will be,

3Ca(NO_3)_2+2Na_3PO_4\rightarrow 6NaNO_3+Ca_3(PO_4)_2

From the balanced chemical reaction, we conclude that

As, 3 moles of calcium nitrate react to give 1 mole of calcium phosphate

So, 0.59 moles of calcium nitrate react to give \frac{1}{3}\times 0.59=0.197 moles of calcium phosphate

Now we have to calculate the mass of calcium phosphate.

\text{Mass of }Ca_3(PO_4)_2=\text{Moles of }Ca_3(PO_4)_2\times \text{Molar mass of }Ca_3(PO_4)_2

\text{Mass of }Ca_3(PO_4)_2=0.197moles\times 310g/mole=61.07g

The theoretical yield of calcium phosphate = 61.07 g

Therefore, the mass of calcium phosphate will be, 61.07 grams

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