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2 years ago

NEED HELP ASAP

Chemistry

1 answer:

sukhopar [10]2 years ago

4 0

Answer:

A= Covalent bonding.

B = Dispersion forces.

Explanation:

This particular question wants to test our knowledge on chemical attractions in molecules. Kindly check the picture attached to get a glimpse of the two forces being compared here.

The force of attraction in B is known as the Dispersion forces. It is the kind of forces of attraction that happens when hydrogen bonds do not happen. Literarily, when Hydrogen atoms reacts with more electronegative atoms such as oxygen, Fluorine and Nitrogen, the kind of bond that will be formed will be an hydrogen bond. So, if hydrogen bond is not formed, then a weaker bond will be formed which is the Dispersion forces of attraction. Hence, B is the Dispersion forces.

Covalent bonds are the kind of bonds that involves that atoms shares electrons in order for chemical bonding to occur. Although, there is H2O which is a polar covalent bond. There are other compounds that are not polar such as CS2 and CH4. Therefore, the kind of attraction in A is covalent bonding.

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Antarctica, almost completely covered in ice, has an area

Marysya12 [62]

Answer: The mass of ice is $2.39\times 10^{22}g$

Explanation:

We are given:

Area of Antarctica = $5,500,000mi^2=5,500,000\times 2.59\times 10^{10}=142.45\times 10^{15}cm^2$ (Conversion factor: $1mi^2=2.59\times 10^{10}cm^2$ )

Height of Antarctica with ice = 7500 ft.

Height of Antarctica without ice = 1500 ft.

Height of ice = 7500 - 1500 = 6000 ft = $182.88\times 10^3cm$ (Conversion factor: 1 ft = 30.48 cm)

To calculate mass of ice, we use the equation:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

Density of ice = $0.917g/cm^3$

Volume of ice = Area × Height of ice = $142.45\times 10^{15}cm^2\times 182.88\times 10^3cm=26051.26\times 10^{18}cm^3$

Putting values in above equation, we get:

$0.917g/cm^3=\frac{\text{Mass of ice}}{26051.26\times 10^{18}cm^3}\\\\\text{Mass of ice}=(0.917g/cm^3\times 26051.26\times 10^{18}cm^3=2.39\times 10^{22}g$

Hence, the mass of ice is $2.39\times 10^{22}g$

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2 years ago

Does the sound wave above experience a change in pitch or loudness? Why?

Basile [38]

My Apoligies for not being sooner.

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General Answer : Its a change in sound, bassically the bigger the waves are, the louder the sound is.

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Fiesta28 [93]

Answer:

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