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Yakvenalex [24]
2 years ago
13

NEED HELP ASAP

Chemistry
1 answer:
sukhopar [10]2 years ago
4 0

Answer:

A= Covalent bonding.

B = Dispersion forces.

Explanation:

This particular question wants to test our knowledge on chemical attractions in molecules. Kindly check the picture attached to get a glimpse of the two forces being compared here.

The force of attraction in B is known as the Dispersion forces. It is the kind of forces of attraction that happens when hydrogen bonds do not happen. Literarily, when Hydrogen  atoms reacts with more electronegative atoms such as oxygen, Fluorine and Nitrogen, the kind of bond that will be formed will be an hydrogen bond. So, if hydrogen bond is not formed, then a weaker bond will be formed which is the Dispersion forces of attraction. Hence, B is the Dispersion forces.

Covalent bonds are the kind of bonds that involves that atoms shares electrons in order for chemical bonding to occur. Although, there is H2O which is a polar covalent bond. There are other compounds that are not polar such as CS2 and CH4. Therefore, the kind of attraction in A is covalent bonding.

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Arrange the following molecules according to the strength of their dispersion forces. Organize in order from largest to smallest
ki77a [65]

Explanation:

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

Therefore, more is the surface area occupied by the carbon chain more will be the dispersion forces present in it. Hence, less is the surface area occupied by a molecule less will be the dispersion forces present in it.  

Hence, the given molecules are organized from largest to smallest dispersion forces as follows.

CH_{3}CH(CH_{3})C(CH_{3})_{2}CH_{2}CH_{3} > CH_{3}CH_{2}(CH_{2})_{4}CH_{2}CH_{3} > CH_{3}CH_{2}CH_{2}CH_{2}CH_{3} > CH_{3}C(CH_{3})2CH_{3} > CH_{3}CH_{2}CH_{3} > CH4

3 0
3 years ago
Calculate the molar concentration of the Br⁻ ions in 0.065 M MgBr2(aq).
steposvetlana [31]
MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
            [Br⁻] = 0.065 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 0.13 M
The answer to this question is [Br⁻] = 0.13 M
4 0
3 years ago
1. Decomposition reactions can be classified into three types. Pick the correct
Alex777 [14]

Answer:

Explanation:

Option A is the correct answer

3 0
3 years ago
A sample of gas in a balloon has an initial temperature of 21 ∘C and a volume of 1310 L . If the temperature changes to 70 ∘C ,
bixtya [17]

Answer:

1528.3L

Explanation:

To solve this problem we should know this formula:

V₁ / T₁ = V₂ / T₂

We must convert the values of T° to Absolute T° (T° in K)

21°C + 273 = 294K

70°C + 273 = 343K

Now we can replace the data

1310L / 294K = V₂ / 343K

V₂ = (1310L / 294K) . 343K → 1528.3L

If the pressure keeps on constant, volume is modified directly proportional to absolute temperature. As T° has increased, the volume increased too

7 0
3 years ago
Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

q=mc \Delta T

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

4 0
3 years ago
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