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4 years ago

Which nonmetal has the greatest potential to be oxidized

Chemistry

1 answer:

Tasya [4]4 years ago

7 0

Answer:

Hydrogen

Explanation:

A reducing agent is a substance which gives up its electrons to become oxidized. Generally, metals are oxidized (reducing agents) while non-metals are reduced (oxidizing agents).

However, hydrogen which is a non-metal is usually oxidized in the presence of stronger oxidizing non-metals such as fluorine and oxygen.

Hydrogen thus, acts as a reducing agent by giving up its electrons to become oxidized. Even though among all non-metals, Hydrogen has the greatest potential to be oxidized, it is a poor reducing agent compared to reactive metals.

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25. What is the order of the types of nuclear radiation from lowest to highest energy?

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Answer:

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Explanation:

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3 years ago

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When ethane (C2H6) burns, it produces carbon dioxide and water:

Hatshy [7]

When 2 moles burn 6 moles of O2 is produced !

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3 years ago

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Is na2S an ionic compound,covalent compound,or acid

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Na2S

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3 years ago

Gaseous methane CH4 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.963

Anna71 [15]

Answer:

$m_{H_2O}=0.676gH_2O$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:

$0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O$

Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:

$m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O$

Regards!

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3 years ago

A chemist requires 0.752 mol na2co3 for a reaction. how many grams does this correspond to?

Sliva [168]

<span>79.70 grams First, calculate the molar mass of Na2CO3 by looking up the molar mass of the elements used in it. Sodium = 22.989769 Carbon = 12.0107 Oxygen = 15.999 Multiply each molar mass by the number of atoms used, and sum the results to get the molar mass 2 * 22.989769 + 12.0107 + 3 * 15.999 =105.9872 Finally, multiply the molar mass by the number of moles you need. 0.752 * 105.9872 = 79.7024 grams</span>

8 0

3 years ago