To answer this, you basically use Pythagoras' Theroem, but instead of:

it will be :

So you are finding the squareroot of the (difference in y coordinates)² plus (difference in x coordinates) ²:
x is the x-coordinate of (0, -1) (so x = 0)
y is the y-coordinte of (0, -1) ( so y = -1)
x1 is the x coordinate of (3, -3) ( so x1 = 3)
y1 is the y coordinate of (3, -3) (so y1 = -3)
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Now, lets find the distance between the two points, by substituting all of this values into the equation at the top:
<em>(substitute in values)</em>
<em>(simplify: note -1 - - 3 = -1 + 3)</em>
<em>(simplify)</em>
<em>(now square the numbers)</em>
<em>(simplify)</em>

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<h3>
Answer:</h3>
C. 