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Y_Kistochka [10]
2 years ago
12

Company A manufactures and sells gidgets. The owners have determined that the company has the monthly revenue and cost functions

shown, such that x represents the number of gidgets sold.
R(x) = 16x
C(x) = 12x + 1,424
At what number of gidgets sold will the company break-even (the point where revenue equals cost)?

A.
480 gidgets
B.
51 gidgets
C.
356 gidgets
D.
119 gidgets
Mathematics
1 answer:
lana [24]2 years ago
4 0

Answer:

Option C.  356 gidgets

Step-by-step explanation:

we have  R(x) ----> the monthly revenue function  C(x) ---> the monthly cost function  x ----> the number of gidgets sold we know that  Break-even means that the revenue equals cost  so  solve for x

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Find the lowest common denominator of and . A. x3y4 B. x2y3 C. xy4 D. x4y5
Blizzard [7]
Lowest Common Denominator refers to lowes t common multiple. These expressions have two terms 'x' and 'y' and we want to choose the expression that has the highest power such that the other expressions can be multiplied into the common denominator.

For the 'x' term, the highest power is x⁴ and for the 'y' term, the highest power is y⁵

Common denominator of A, B, C, and D: x⁴y⁵




5 0
3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
3 years ago
S is inversely proportional to t<br> When s = 0.5, t = 7<br> Work out s when t = 0.8
defon

Given:

s is inversely proportional to t.

When s = 0.5, t = 7.

To find:

The value of s when t=0.8.

Solution:

s is inversely proportional to t.

s\propto \dfrac{1}{t}

s=\dfrac{k}{t}       ...(i)

Where, k is the constant of proportionality.

Putting s=0.5 and t=7, we get

0.5=\dfrac{k}{7}

0.5\times 7=k

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Putting k=3.5 in (i), we get

s=\dfrac{3.5}{t}

This is the equation of proportionality.

Putting t=0.8, we get

s=\dfrac{3.5}{0.8}

s=4.375&#10;

Therefore, the value of s is 4.375 when t=0.8.

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