1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OverLord2011 [107]
3 years ago
8

1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o

f the figure?
2. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?
3. What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the
width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​
Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

You might be interested in
Mr. McGloughlin’s horses eat a total of 19 liters 2 deciliters of rolled oats, and drink a total of 46 liters 4 deciliters of wa
Hunter-Best [27]

Answer:

459.2 liters.

Step-by-step explanation:

Let us convert our given amount of rolled oats and water in deciliters.

1 liter = 10 deciliters

19 liters = 19*10 deciliters = 190 deciliters.

\text{Total amount of rolled oats consumed per day}=(190+2)\text{ deciliters}

\text{Total amount of rolled oats consumed per day}=192\text{ deciliters}

46 liters=46*10=460 deciliters

\text{Total amount of water consumed per day}=(460+4)\text{ deciliters}

\text{Total amount of water consumed per day}=464\text{ deciliters}

Now let us find weekly consumption of oats and water by multiplying daily consumption of both items by 7.

\text{Total weekly consumption of oats and water}=7*(464+192)\text{ deciliters}

\text{Total weekly consumption of oats and water}=7*(656)\text{ deciliters}  

\text{Total weekly consumption of oats and water}=4592\text{ deciliters}

Let us convert weekly consumption of water and oats into liters.

\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10\frac{\text{ deciliters}}{\text{liter}}}  

\text{Total weekly consumption of oats and water}=\frac{4592\text{ deciliters}}{10}\cdot\frac{\text{ liters}}{\text{ deciliters}}}

\text{Total weekly consumption of oats and water}=\frac{4592}{10}\text{ liters}

\text{Total weekly consumption of oats and water}=459.2\text{ liters}

Therefore, total weekly combined consumption of oats and water is 459.2 liters.

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to 1 over 5 m − 20?
laiz [17]

1

-----------

5m -20


factor out a 5 in the denominator

1

-----------

5 (m -4)


Choice A

7 0
3 years ago
Stephanie is a taxi driver. She rents her taxi for $300/week. She feels she can take in $120/day in fares. Let D be the number o
Lesechka [4]

Answer: a. (0, -300), (1, -180), (2, -60), (7, 540)

b. T=120D-300

c. $28080

Step-by-step explanation:

a. T=120D-300 ==> per week

D=0: T=120(0)-300

D=0: T=-300 ==> (0, -300)

D=1: T=120(1)-300

D=1: T=120-300

D=1: T=-180 ==> (1, -180)

D=2: T=120(2)-300

D=2: T=240-300

D=2: T=-60 ==> (2, -60)

D=7: T=120(7)-300

D=7: T=840-300

D=7: T=540 ==> (7, 540)

b. T=120D-300

c. T=120(7)-300

T=840-300

T=$540 per week

1 year = 52 weeks

540*52=$28080

6 0
2 years ago
Use the pic for more info will mark brainlest
Lelechka [254]

Answe7.5 i think

Step-by-step explanation:

4 0
3 years ago
Which number is a solution of the inequality? b &gt; 11.3; 9 –14 15 4
marshall27 [118]

b > 11.3\\\\9-NOT,\ because\ 9\ is\ not\ greater\ than\ 11.3\\-14-NOT,\ because\ -14\ is\ not\ greater\ than\ 11.3\\15-YES,\ because\ 15>11.3\\4-NOT,\ because\ 4\ is\ not\ greater\ than\ 11.3\\\\Answer:\ \boxed{15}

6 0
3 years ago
Other questions:
  • The sum of triple a number and 4 is nine how do I write an equation to represent this problem
    6·2 answers
  • If one serving of punch is 250 ml will ten servings fit in a two liter bowl
    6·1 answer
  • How do I solve (z+7)^2=3
    14·1 answer
  • A sphere and a cylinder have the same radius and height. The volume of the cylinder is 30 m
    7·1 answer
  • Nine thousand and ninety​
    13·2 answers
  • The total for the two items (without tax) was $151.48. The price of the backpack was $65.49. What was the price of the calculato
    14·1 answer
  • What is the slope and y-intercept -4x+2y=-2
    10·1 answer
  • Please help asap tysm n ily &lt;3
    14·2 answers
  • Write the inequality graphed on the number line.<br><br> -3 3
    13·1 answer
  • Please help! i will give you a lot of points if you do!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!