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stellarik [79]
3 years ago
11

True or False, Weather is the long term average conditions in an area. Group of answer choices.

Physics
1 answer:
Lemur [1.5K]3 years ago
5 0
The answer to your question is false
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Say you have a differential drive robot that has an axle length of 30cm and wheel diameter of 10cm. Find the angular velocity fo
Klio2033 [76]

Answer:

a) ω1 = 18rpm    ω2 = -18rpm

b) ω1 = 102rpm     ω2 = 138rpm

c) ω1 = ω2 = 3.18rpm

Explanation:

For the first case, we know that each wheel will spin in a different direction but with the same magnitude, so:

ωr = 6rpm   This is the angular velocity of the robot

\omega = \frac{\omega r * D/2}{r_{wheel}}  where D is 30cm and rwheel is 5cm

\omega = \frac{6 * 30/2}{5}=18rpm  One velocity will be positive and the other will be negative:

ω1 = 18rpm    ω2 = -18rpm

For part b, the formula is the same but distances change. Rcircle=100cm:

\omega 1 = \frac{\omega r * (R_{circle} - D/2)}{r_{wheel}}

\omega 2 = \frac{\omega r * (R_{circle} + D/2)}{r_{wheel}}

Replacing values, we get:

\omega 1 = \frac{6 * (100 - 30/2)}{5}=102rpm

\omega 2 = \frac{\omega r * (100 + 30/2)}{5}=138rpm

For part c, both wheels must have the same velocity:

\omega = \frac{V_{robot}}{r_{wheel}}=20rad/min

\omega = 20rad/min * \frac{1rev}{2*\pi rad}=3.18rpm

8 0
4 years ago
Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c
11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}

And plug in the numbers we are given:

\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}

Learn more about ideal gases: brainly.com/question/26450101

5 0
3 years ago
The weight of an object on a planet depends not only on its mass, but also on its distance from the planets center. Uranus has m
Ierofanga [76]
The further an object is from the centre of a planet, the lower it's gravitational force. Uranus had 14 times as much mass as earth, but it's also a lot bigger than earth. So assuming an object is on the surface of Uranus, it would be really far away from the centre of Uranus, therefore the gravitational force is less.

Hope this helps!
5 0
3 years ago
Read 2 more answers
How the properties of sound waves change as they spread out in a spherical pattern
Vlad1618 [11]
It is when the air hit the wave and it moves to another direction.
6 0
3 years ago
If the electric charge on the object is tripled while its mass remains the same, find the direction and magnitude of its acceler
maksim [4K]
F = qE = mg

E = mg/q = 0.017*9.81('-3.1x10^-6) = 5.38x10^4 = -53,800 N/C

E' = 0.5E = -26,900N/C 

 2q -mg= ma, Answer is 9.81 m/s^2  and it's positive because the force is upward.
8 0
3 years ago
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