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maks197457 [2]
3 years ago
5

How much force is needed to stop a 50 kg gymnast if he decelerates at 25 m/s^2

Physics
1 answer:
vlada-n [284]3 years ago
3 0
The force can be calculated by multiplying the mass of the gymnast with her acceleration.

Force = 50 kg × 25 m/s2
Force = 1250 N

A force of at least 1250 N can stop the 50-kg gymnast.

I hope I was able to answer your question. Have a good day.
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The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

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3 years ago
Vector a has a magnitude of 12.3 units and points due west. vector b points due north. what is the magnitude of b if a - b has a
algol [13]

The magnitude of vector b is 8.58 Unit.

Since both the vectors a and b are perpendicular to each other, so we can apply the Pythagoras theorem to calculate the magnitude of the vector b.

Applying the Pythagoras theorem

(a-b)^2=a^2+b^2

15^2=12.3^2-b^2

b=8.58 unit

Therefor the magnitude of the vector b is 8.58 unit.

8 0
3 years ago
A 49.3 g ball of copper has a net charge of 2.0 µc. what fraction of the copper's electrons has been removed? (each copper atom
Serggg [28]
First, find how many copper atoms make up the ball: 
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<span> There is normally one electron for every proton in copper. This means there are normally 29 electrons per atom:
</span> normal # electrons = (4.6738 × 10^23 atoms) (29 electrons per atom) = <span> <span>1.3554</span></span><span>× 10^25 electrons 
</span>
<span> Currently, the charge in the ball is 2.0 µC, which means -2.0 µC worth of electrons have been removed.
</span><span> # removed electrons = (-2.0 µC) / (1.602 × 10^-13 µC per electron) = 1.2484 × 10^13 electrons removed
 
</span><span> # removed electrons / normal # electrons = </span>
<span>(1.2484 × 10^13 electrons removed) / (1.3554 × 10^25 electrons) = 9.21 × 10^-13 </span>

<span> That's 1 / 9.21 × 10^13 </span>
7 0
3 years ago
What two kinds of motion combine to produce projectile motion?
Vikki [24]

Horizontal and Vertical are the two motions that combine to produce projectile motion.

4 0
3 years ago
2 kg and 3 kg objects slide together, and then they break apart. If the final velocity of 2 kg is 10 m/s,
lara [203]

Answer:

P = (2 + 3) * V       where V is their initial speed  (total momentum)

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If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.

Also work depends on the sum of the velocities

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It appears that more information is required for this problem

8 0
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