671,079,600 mph
hope you'll give me the brainliest!
Answer:x=2, y=1, z=-1
Step-by-step explanation:
Given
2x+y+z=4----1
x-y+3z=-2----2
-x+y+z=-2----3
Add 2 & 3 we get
4z=-4
z=-1
Put value of z in 1 & 2
2x+y-1=4
2x+y=5----3
x-y+3(-1)=-2
x-y=1------4
add 3 & 4 we get
x=2
Put x & z in 1
y=1
The plane you want is parallel to another plane, <em>x</em> - <em>y</em> + <em>z</em> = -5, so they share a normal vector. In this case, it's ⟨1, -1, 1⟩.
The plane must also pass through the point (0, 4, 4) since it contains <em>r</em><em>(t)</em>. Then the equation of the plane is
⟨<em>x</em>, <em>y</em> - 4, <em>z</em> - 4⟩ • ⟨1, -1, 1⟩ = 0
<em>x</em> - (<em>y</em> - 4) + (<em>z</em> - 4) = 0
<em>x</em> - <em>y</em> + <em>z</em> = 0
Answer:
what am i supposed to be looking at u didnt
put in thr answersStep-by-step explanation:
