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3 years ago

What is the minimum recommended safe distance from an X-ray source?

Engineering

2 answers:

lara31 [8.8K]3 years ago

3 0

Hi! I believe the answer is 2 meters(:

otez555 [7]3 years ago

3 0

The answer is 2mater

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Why is sssniperwolf so fine

RSB [31]

Bc she’s just a baddie

5 0

3 years ago

Read 2 more answers

A gas stream contains 18.0 mole% hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is re

Anna [14]

Answer:

A. 72.34mol/min

B. 76.0%

Explanation:

We start by converting to molar flow rate. Using density and molecular weight of hexane

= 1.59L/min x 0.659g/cm³ x 1000cm³/L x 1/86.17

= 988.5/86.17

= 11.47mol/min

n1 = n2+n3

n1 = n2 + 11.47mol/min

We have a balance on hexane

n1y1C6H14 = n2y2C6H14 + n3y3C6H14

n1(0.18) = n2(0.05) + 11.47(1.00)

To get n2

(n2+11.47mol/min)0.18 = n2(0.05) + 11.47mol/min(1.00)

0.18n2 + 2.0646 = 0.05n2 + 11.47mol/min

0.18n2-0.05n2 = 11.47-2.0646

= 0.13n2 = 9.4054

n2 = 9.4054/0.13

n2 = 72.34 mol/min

This value is the flow rate of gas that is leaving the system.

n1 = n2 + 11.47mol/min

72.34mol/min + 11.47mol/min

= 83.81 mol/min

Amount of hexane entering condenser

0.18(83.81)

= 15.1 mol/min

Then the percentage condensed =

11.47/15.1

= 7.59

~7.6

7.6x100

= 76.0%

Therefore the answers are a.) 72.34mol/min b.) 76.0%

Please refer to the attachment .

4 0

3 years ago

1. A turbine in a steam power plant operates isentropically with an inlet pressure (P3) of 3.5 MPa and inlet temperature (T3) of

sergey [27]

Answer:

See attached picture.

Explanation:

See attached picture for explanation.

4 0

3 years ago

Suppose that the weights for newborn kittens are normally distributed with a mean of 125 grams and a standard deviation of 15 gr

kherson [118]

(a) If a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

(b) For a kitten to be at 90th percentile, the minimum weight is 146.45 g.

<h3>Weight distribution of the kitten</h3>

In a normal distribution curve;

2 standard deviation (2d) below the mean (M), (M - 2d) is at 2%

1 standard deviation (d) below the mean (M), (M - d) is at 16 %
1 standard deviation (d) above the mean (M), (M + d) is at 84%
2 standard deviation (2d) above the mean (M), (M + 2d) is at 98%

M - 2d = 125 g - 2(15g) = 95 g

M - d = 125 g - 15 g = 110 g

95 g is at 2% and 110 g is at 16%

(16% - 2%) = 14%

(110 - 95) = 15 g

14% / 15g = 0.93%/g

From 95 g to 99 g:

99 g - 95 g = 4 g

4g x 0.93%/g = 3.72%

99 g will be at:

(2% + 3.72%) = 5.72%

Thus, if a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

<h3>Weight of the kitten in the 90th percentile</h3>

M + d = 125 + 15 = 140 g (at 84%)

M + 2d = 125 + 2(15) = 155 g ( at 98%)

155 g - 140 g = 15 g

14% / 15g = 0.93%/g

84% + x(0.93%/g) = 90%

84 + 0.93x = 90

0.93x = 6

x = 6.45 g

weight of a kitten in 90th percentile = 140 g + 6.45 g = 146.45 g

Thus, for a kitten to be at 90th percentile, the approximate weight is 146.45 g

Learn more about standard deviation here: brainly.com/question/475676

#SPJ1

7 0

2 years ago

Design roller chain drive. Specify the chain size, the sizes and number of teeth in the sprockets, the number of chain pitches,

Rom4ik [11]

Answer:

The total design can be summarized as follows:

AC motor 55 hp, 750 rpm as a driver

Service factor 1.0

Design power 5 hp

No. 40 chain, 0.50 in pitch, 1 strands

17 teeth, 2.72 in pitch dia, 1 strand small sprocket

39 teeth, 7.46 in pitch dia, 1 strand large sprocket

1 strand of length 54 in

Center distance of 19.9 in

Actual Output speed of 326.9 rpm

Type B lubrication

Explanation:

4 0

3 years ago