Proof by contradiction is a form of proof that establishes the truth or the validity of a proposition, by showing that assuming the proposition to be false leads to a contradiction. I googled this so it may not be correct
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
16 crates to hold all 128 cases of trading cards
Answer:
- 2 1/10
Step-by-step explanation:
-2/5 -x -9/10
Let x = 4/5
-2/5 - 4/5 - 9/10
Combine like terms
-6/5 - 9/10
Get a common denominator of 10
-6/5 * 2/2 - 9/10
-12/10 - 9/10
-21/ 10
Change this to a mixed number
10 goes into 21 2 times with 1 left over
-2 1/10
Answer:
25
Step-by-step explanation:
Let's call the missing side (the hypotenuse) c.
c² = 7²+24² (according to the pythagorean theorem)
c= 
c=25