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rewona [7]
3 years ago
8

How to write the of the cube of a number and 27 in algebraic expression?

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0

should be:

x^3 + 27

hope it helps

Korolek [52]3 years ago
4 0
Should be iam not sure but it should be x^3+27
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You can see below!

Step-by-step explanation:

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mixas84 [53]
<span>The correct answer is 216x</span>⁶<span>y</span>⁵<span>.

Explanation:
The first thing we do is raise the last monomial to the third power.

(4xy)(2x</span>²<span>y)(3xy)</span>³
<span>=(4xy)(2x</span>²<span>y)(3</span>³<span>x</span>³<span>y</span>³<span>)
=4xy(2x</span>²<span>y)(27x</span>³<span>y</span>³<span>).

Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
8x</span>³<span>y</span>²<span>(27x</span>³<span>y</span>³<span>).

We multiply these last two monomials, again adding the exponents:
216x</span>⁶<span>y</span>⁵<span>.</span>
3 0
3 years ago
Read 2 more answers
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