The state of matter for an object that has both definite volume and definite shape is

Chemistry

1 answer:

Romashka-Z-Leto [24]4 years ago

3 0

The state of matter for an object that has both definite volume and definite shape is solid.

You might be interested in

Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen produced 2.086 g of CO2 and 1.134

timurjin [86]

<span>the empirical formula is C3H8O2 You need to determine the relative number of moles of hydrogen and carbon. So you first calculate the molar mass of CO2 and H20 Atomic weight of carbon = 12.0107 Atomic weight of hydrogen = 1.00794 Atomic weight of oxygen = 15.999 Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488 Now calculate the number of moles of CO2 and H2O you have Moles CO2 = 2.086 g / 44.0087 g/mole = 0.0474 mole Moles H2O = 1.134 g / 18.01488 g/mole = 0.062948 mole Calculate the number of moles of carbon and hydrogen you have. Since there's 1 carbon atom per CO2 molecule, the number of moles of carbon is the same as the number of moles of CO2. But since there's 2 hydrogen atoms per molecule of H2O, The number of moles of hydrogen is double the number of moles of H2O Moles Carbon = 0.0474 Moles Hydrogen = 0.062948 * 2 = 0.125896 Now we need to determine how much oxygen is in the compound. Just take the mass of the compound and subtract the mass of carbon and hydrogen. What's left will be the mass of oxygen. Then divide that mass by the atomic weight of oxygen to get the number of moles of oxygen we have. 1.200 - 0.0474 * 12.0107 - 0.125896 * 1.00794 = 0.503797 Moles oxygen = 0.503797 / 15.999 = 0.031489 So now we have a ratio of carbon:hydrogen:oxygen of 0.0474 : 0.125896 : 0.031489 We need to find a ratio of small integers that's close to that ratio. Start by dividing everything by 0.031489 (selected because it's the smallest value) getting 1.505288 : 3.998095 : 1 The 1 for oxygen and the 3.998095 for hydrogen look close enough. But the 1.505288 for carbon doesn't work. But it looks like if we double all the numbers, we'll get something close to an integer for everything. So do so. 3.010575 : 7.996189 : 2 Now this looks good. Rounding everything to an integer gives us 3 : 8 : 2 So the empirical formula is C3H8O2</span>

5 0

3 years ago

In the united states, east coast pollutants get blown to

3241004551 [841]

Explanation:

smoking is the main reason

4 0

3 years ago

Is every solution also a mixture?

aleksandrvk [35]

A mixture consists of two or more components. a solution can consists of a solute dissolved in a solvent or two solvents mixed together, for instance. A mixture can also be two gases (CO2 and O2) mixed together or two solids mixed together (sawdust and chalk).

4 0

4 years ago

*aluminium ,chromium manganese are all moderately reactive metals use the following information to arrange them in the correct r

ArbitrLikvidat [17]

The order:

$\mathrm{Al : \: Most \: reactive, reduces \: everyone!(here)}\\\mathrm{Mn}\\\mathrm{Cr}$

8 0

4 years ago

A 2.0 l container of oxygen had a pressure of 3.2 atm. what volume would be necessary to decrease the pressure to 1.0 atm? use t

aivan3 [116]

The volume that would be necessary to decrease the pressure to 1.0 atm is mathematically given as

v2=6.4l

<h3>What volume would be necessary to decrease the pressure to 1.0 atm?</h3>

Question Parameter(s):

A 2.0 l container of oxygen had a pressure of 3.2 atm

Generally, the equation for the is mathematically given as

P1v1=p2v2

Therefore

v2=piv1/p2

v2=2*3.2/1

v2=6.4l

In conclusion, the volume is

v2=6.4l