Answer:
The proper matching is given below.
Explanation:
a Separate molecules by size size exclusion chromatography
b Separate molecules by charge Ion exchange chromatography
c The stationary phase has a covalently bound group to which a protein in the mobile phase can bind. Affinity chromatography
d uses mobile phase and stationary phase to separate protein Size exclusion chromatography
e The stationary phase contain cross linked polymers with different pore size
Size exclusion chromatography
f can separate molecules based on protein ligand binding Affinity chromatography
g The stationary phase may contain negatively or positively charged groups
ion exchange chromatography
<span>Baking a cake is an example of making something where the ingredients must be in fixed ratios. Recipes call for specific ratios of ingredients in order to cook properly, and when a recipe for a cake is modified to feed greater or fewer people the ratio remains the same as the original recipe.</span>
Answer:
The mass of an object is the same no matter where it is, but the weight of an object changes with the location of that object. For example, the weight of an object on the Moon is 1/6th that of the same object on Earth, while the mass of that object is exactly the same in both places.
Explanation:
Sited: https://howthingsfly.si.edu/ask-an-explainer/what’s-difference-between-mass-and-weight
Answer:
Explanation:
Concepts and reason
This problem is based on the concept of hydrolysis of esters.
An ester is hydrolyzed to a carboxylic acid and an alcohol when treated with aqueous acid or aqueous base. Under alkaline conditions, the carboxylic acid is obtained in the form as its salt.
Fundamentals
Alkaline hydrolysis of ester is done with strong base {\\rm{NaOH}}NaOHand {\\rm{O}}{{\\rm{H}}^ - }OH\u2212acts as nucleophilic reagent. This reaction is reversible, since carboxylate anion has tendency to react with an alcohol and gives back ester.
Step-by-step
Step 1 of 2
Attack of [{ m{O}}{{ m{H}}^ - }]on carbonyl take place as follows resulting formation of tetrahedral intermediate:
\u043e\u043d\u043e\u043d
Explanation | Hint for next step
The {\\rm{O}}{{\\rm{H}}^ - }OH\u2212nucleophile attacks on the electrophilic carbon of an ester {\\rm{C}} = {\\rm{O}}C=O and forms tetrahedral intermediate after breaking the \\pi\u03c0-bond.
Step 2 of 2
Hydrolysis of product formed from step 1 followed by reaction with {\\rm{NaOH}}NaOHis as follows:
The products of the reaction are:
Explanation | Common mistakes
On the reaction of octyl acetate with aqueous sodium hydroxide, the products octyl alcohol and acetate ion are formed after omitting the {\\rm{N}}{{\\rm{a}}^ + }Na+ions.