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Westkost [7]
3 years ago
15

What do an electron and a neutron have in common?

Chemistry
2 answers:
zmey [24]3 years ago
4 0
What an electron and a neutron have in common is that <u>each particle exists inside an atom,</u>
Atoms consist of three particles: protons (which are positively charged), electrons (which are negatively charged), and neutrons (which have no charge). 
Georgia [21]3 years ago
3 0

Answer:

Each particle exists inside an atom.

Explanation:

U DARE QUESTION THE WORDS OF THE MIGHTY JIMMY?!

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DENIUS [597]

Answer:

jesus

Explanation:

Jesus is always the answer LOL

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2 years ago
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The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hou
STatiana [176]

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

m = 6400 ÷ 7.77

m = 823.7g

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Answer:

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3 years ago
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Density is considered what type of property
Taya2010 [7]
Density is a physical property. It's measured and doesn't change the object chemically.
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