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3 years ago

What do an electron and a neutron have in common?

2 answers:

4 0

What an electron and a neutron have in common is that <u>each particle exists inside an atom,</u>
Atoms consist of three particles: protons (which are positively charged), electrons (which are negatively charged), and neutrons (which have no charge).

Georgia [21]3 years ago

3 0

Answer:

Each particle exists inside an atom.

Explanation:

U DARE QUESTION THE WORDS OF THE MIGHTY JIMMY?!

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What is the graph of the orange line and is it a positive or negative connotation

dimulka [17.4K]

Answer:

Positive

Explanation:

4 0

2 years ago

He particles are mostly free of each other influence is solid , liquid , gas

Simora [160]

the most free particles are gases, then liquids, solids

4 0

3 years ago

.....................?

liraira [26]

Answer:

Look at the periodic table of elements

Explanation:

Group 1 is the most reactive and to the right

Group 18 is least reactive and all the way to the left. The rest are in between. The groups go vertical.

You'd be able to solve with this information youre welcome

4 0

2 years ago

Calculate volume of carbon dioxide gas if the mass is 88.0 g at 20.0°C and 950mmHg

aivan3 [116]

Answer:

Tam tam fdjknf

Explanation:

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7 0

3 years ago

What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O

nadya68 [22]

Answer:

$V=43.46mL$

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

$n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4$

Then, given the molarity, it is possible to obtain the milliliters as follows:

$V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL$

Best regards!

7 0

2 years ago