Answer:
32.07%
Step-by-step explanation:
53 total
36 completed
Remaining = 53 - 36 = 17
17/53
= 0.3207
= 32.07%
$230.55
15 x 1537 = 23055 / 100
= 230.55
<em>A player has made 188 free throw attempts, and in that time has made a total of 129 free throws. FT % = 0.686 Therefore, this player has an FT% of .686, or 68.6%. Wikipedia – Free throw percentage season leaders and Free Throw (Basketball) – Wikipedia entries on the concept of free throws.</em>
Just count how many times a given age appears in the data. If my eyes aren't deceiving me, I count
• 26: 3
• 27: 5
• 28: 5
• 29: 5
• 30: 2
• 31: 1
• 33: 4
Then the second most frequent age in the data is 33, and the least frequent is 31.
I don’t know I’m just doing this for the points I’m sorry ☮️✌️