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anyanavicka [17]
3 years ago
11

Are my answers correct? if not what should they be?

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

What is the question for the exercise?

Step-by-step explanation:

Tell me, and I might help u

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A ball is dropped from a height of 125 cm. Each time it hits the ground, it bounces
zalisa [80]

As a decimal 3/5 = 0.6

Multiply the height by 0.6:

1st bounce = 125 x 0.6 = 75

2nd bounce = 75 x 0.6 = 45

3rd bounce = 45 x 0.6 = 27

The answer is 27cm

5 0
3 years ago
Read 2 more answers
Please help me please
Ne4ueva [31]

Answer:

104 + 3(90.50)

Step-by-step explanation:

Always do what's inside the parenthesis first.

PEMDAS

4 0
3 years ago
The distance of a point P(x, y) from the origin O(0, 0) is given by OP=__​
Naily [24]

Answer:-

\boxed{\sf \sqrt{x^2+y^2}}

Explanation:-

  • P(x,y)
  • O(0,0)

We know distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

\\ \sf\longmapsto OP=\sqrt{(0-x)^2+(0-y)^2}

\\ \sf\longmapsto OP=\sqrt{(-x)^2+(-y)^2}

\\ \sf\longmapsto OP=\sqrt{x^2+y^2}

4 0
3 years ago
Please help me find the answer​
Butoxors [25]

C. might be the answer

6 0
3 years ago
How can you determine the relationship between corresponding terms? Give an example.
stellarik [79]
You have to try to determine the sequence, and you try two basic kind of sequences: aritymethic and geometric.

In aritmetic sequeces the relationships is that the difference between any adjacent terms is constant.

For example

´Number of term (n)     Term, An

1                                   7

2                                   11

3                                   15

4                                   19

Then the relationship between adjacent terms is 19 - 15 = 4 = 15 -11 = 4 = 11 - 7 = 4.

You can find, then, a general expression that relates any term with its position.

It is An = 7 + (n-1)*4

In geometric sequences the relationship is found dividing two adjacent terms, because the ratio is constant.

For example:

Number of term     Term

1                            10
2                            20
3                            40
4                            80

You can then find the relation as: 20/10 = 2 = 40/20 = 2 = 80/40 = 2.

In this case the general term is An = 10 * 2^ (n-1) 
3 0
3 years ago
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