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krok68 [10]
3 years ago
14

The fundamental (LaTeX: n=1 n = 1 harmonic or mode) frequency created on a stretched string with fixed ends occurs when the stri

ng is driven at a frequency of 50 Hz. If the tension in this string is doubled without changing its mass density, what would be the new fundamental frequency?
Physics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:\sqrt{2}f

Explanation:

Given

Fundamental Frequency(f) is 50 Hz

and frequency is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu }}---1

Where T= tension

\mu=mass per unit length

if tension is doubled

f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu }}---2

Divide 1& 2

\frac{f}{f'}=\sqrt{\frac{T}{2T}}

f'=\sqrt{2}f

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A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni
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