Answer:
λ = 2.62 x 10⁻¹⁰ m = 0.262 nm
Explanation:
We can use Bragg's Law's equation to solve this problem. The Bragg's Law's equation is written as follows:
mλ = 2d Sin θ
where,
m = order of reflection = 1
λ = wavelength = ?
d = distance between the planes of crystal = 3.5 x 10⁻¹⁰ m
θ = strike angle of waves on plane = 22°
Therefore, substituting the respective values in the equation, we get:
(1)λ = (2)(3.5 x 10⁻¹⁰ m)(Sin 22°)
<u>λ = 2.62 x 10⁻¹⁰ m = 0.262 nm</u>
since airplane is thrown towards west with speed 6 m/s
while air is blowing with speed 8 m/s towards north
so here the net speed of air plane will be the resultant of airplane speed and wind speed always
SO here we can say it would be a combination of vector along west with must be of length 6 m/s and other vector is towards north with is of length 8 m/s
so correct answer must be 1st option
Weathering, Erosion, deposition, acid rain, precipitation
Explanation:
Answer:
The equation of equilibrium at the top of the vertical circle is:
\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}
The speed experimented by the car is:
\frac{N}{m}+g=\frac{v^{2}}{R}
v = \sqrt{R\cdot (\frac{N}{m}+g) }
v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}
v\approx 9.302\,\frac{m}{s}
The equation of equilibrium at the bottom of the vertical circle is:
\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}
The normal force on the car when it is at the bottom of the track is:
N=m\cdot (\frac{v^{2}}{R}+g )
N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)
N=21.690\,N
Answer:
C
Explanation:
hope for help ....im expert
