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Tom [10]
3 years ago
14

The first outside orbit of Earth planet is a Jupiter b Mars c Saturn d uranus​

Physics
2 answers:
sp2606 [1]3 years ago
8 0
<h3>B, Mars is the correct answer.</h3>

<h2> Thank you ☺️☺️</h2>
horsena [70]3 years ago
3 0

Answer:

I believe it would be B, Mars.

Hope this helps!

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What is the farthest distance parallaxes can be used to measure star distances from Earth?
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Using current technology, useful parallax measurements can only be found for stars up to about 340 light years (100 parsecs) away.
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A wire runs left to right and carries a current in the direction shown.
Step2247 [10]

Answer:

The direction of the magnetic field at point Z; Into the screen

Explanation:

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The planet should move around the elliptical orbit, and two segments of the orbit should become shaded in green. What aspect(s)
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In boxing, the use of 16-ounce gloves rather than 12-ounce gloves reduces the chance of injury because the force is distributed
mr Goodwill [35]

Answer:

true

Explanation:

Here we have assumed that increasing the mass of a glove will increase the surface area.

Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by

P=\dfrac{F}{A}

where

F = Force

A = Area to which the force is applied

So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.

Hence, the statement is true.

5 0
3 years ago
A truck of mass 200kg rests on an inclined plane hindered from rolling down the surface by a storing sprint whose force constant
mixas84 [53]

Answer:

1.92 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 200 Kg

Spring constant (K) = 10⁶ N/m

Workdone =?

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass (m) = 200 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = m × g

F = 200 × 9.8

F = 1960 N

Next we shall determine the extent to which the spring stretches. This can be obtained as follow:

Spring constant (K) = 10⁶ N/m

Force (F) = 1960 N

Extention (e) =?

F = Ke

1960 = 10⁶ × e

Divide both side by 10⁶

e = 1960 / 10⁶

e = 0.00196 m

Finally, we shall determine energy (Workdone) on the spring as follow:

Spring constant (K) = 10⁶ N/m

Extention (e) = 0.00196 m

Energy (E) =?

E = ½Ke²

E = ½ × 10⁶ × (0.00196)²

E = 1.92 J

Therefore, the Workdone on the spring is 1.92 J

3 0
2 years ago
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