Answer:
Mode of transportation and source of energy
Energy sources are used in several major ways
Gasoline is used in cars, motorcycles, light trucks, and boats. Aviation gasoline is used in many types of airplanes. Distillate fuels are used mainly by trucks, buses, and trains and in boats and ships. Jet fuel is used in jet airplanes and some types of helicopters.
Explanation:
Answer:
Explanation:
count given by old sample = .97 disintegrations per minute per gram
count given by fresh sample = 6.68 disintegrations per minute per gram
Half life of radioactive carbon = 5568 years
rate of disintegration
dN / dt = λ N
In other words rate of disintegration is proportional to no of radioactive atoms present . As number reduces rate also reduces .
Let initial no of radioactive be N₀ and after time t , number reduces to N
N₀ / N = 6.68 / .97
Now



λ is disintegration constant
λ = .693 / half life
= .693 / 5568
= .00012446 year⁻¹
Putting the values in the equation above


1.929577 = .00012446 t
t = 15503.6 years .
The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).
<h3>How to calculate volume?</h3>
The volume of a substance can be calculated using the following formula:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
153 × 3 = 304 × V2
459 = 304V2
V2 = 459/304
V2 = 1.51L
Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.
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The theoretical yield is the reaction yield that measures the product of the reaction from the conversion of the limiting reagent. The theoretical yield is 160 gm.
<h3>What is mass?</h3>
Mass or the theoretical yield is the result of the multiplication of mole and the molar mass of the compound.
The reaction between hydrogen and oxygen is shown as,

Moles of water is calculated as:

The theoretical yield of water is calculated as:

Therefore, option D. 160 gm is the theoretical yield of water.
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Answer:
Chloroform is expected to boil at 333 K (60
).
Explanation:
For liquid-vapor equilibrium at 1 atm,
= 0.
We know,
, where T is temperature in kelvin scale.
Here both
and
are corresponding to vaporization process therefore T represents boiling point of chloroform.
So, ![0=(31.4\times 10^{3}\frac{J}{mol})-[T\times (94.2\frac{J}{mol.K})]](https://tex.z-dn.net/?f=0%3D%2831.4%5Ctimes%2010%5E%7B3%7D%5Cfrac%7BJ%7D%7Bmol%7D%29-%5BT%5Ctimes%20%2894.2%5Cfrac%7BJ%7D%7Bmol.K%7D%29%5D)
or, T = 333 K
So, at 333 K (60
) , chloroform is expected to boil.