The amount of joules of heat that are lost when 150.0 g of steam are cooled from 124 °c to 86 °c is = -11343 joules
calculation
heat(Q) = mass(m) x specific heat capacity(C) x change in temperature (ΔT)
where,
Q=? joules
M=150.0 g
C for steam = 1.99 j/g/°c
ΔT= 86°c-124°c = -38°c
Q is therefore = 150.0 g x 1.99 j/g/°c x -38°c =-11343 joules
Answer: Convection, Conduction, and radiation
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Answer: 195.3 K
Explanation: Use Charles Law to get T2
Charles Law V1 / T1 = V2 / T2
Derive the equation to find T2
T2 = V2T1 / V1
Convert temperature into K
T1 = 20.0 °C + 273 = 293 K
Substitute the values:
4.00 L x 293 K / 6.00 L = 195. 3 K
Moles Chlorine to grams = 35.453 grams.
moles Chlorine to grams = 70.906 grams.
moles Chlorine to grams = 106.359 grams.
moles Chlorine to grams = 141.812 grams.
moles Chlorine to grams = 177.265 grams.
moles Chlorine to grams = 212.718 grams.
