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4vir4ik [10]
3 years ago
12

Element X has the following valence electron configuration: [core]ns2np5. Element M has the following valence electron configura

tion: [core]ns2. What ionic compound would most likely result from the reaction between ions of M and X?
Chemistry
1 answer:
alex41 [277]3 years ago
6 0

Answer:

The kind of ionic compound formed is MX2.

Explanation:

Element X electron  configuration is represented as [core] ns2np5. The group in the periodic table this element belong to is group 7A.  The element group is called the halogen family. Element X cannot be stated specifically, because the number is represented with n.  Element X will behave as an anions when it react with a metal(cations). Element X has a charge of -1. The element X will gain electron when it bond with a metal. Element X is a non metal . Elements  in this group are fluorine, chlorine, bromine, iodine , astatine, and tennessine . The element X have 7 valency electrons.

Element M electronic configuration is represented as  [core]ns2. The group in the periodic table this element belong to is group 2A . The element  group is called the alkaline earth metals family . Element M will behave as a cation when it bond with a non metal. Element M is a metal , therefore it will likely lose electron to form cations during bonding . The charge of element M is 2+. Element M is positively charged. Elements that belong to this group includes beryllium, magnesium, calcium, strontium, barium and radium.  Element M has 2 valency electrons.

The reaction between this 2 ions will likely form an ionic compound . The element M is the cations while the element X is the anions. The element M will lose 2 electron while 2 atoms of element  X will gain 2 electrons.Element M will lose 2 electron to attain a stable configuration while 2 atoms of element X will gain a single electron each to attain a stable configuration.

M²+ and F- . This will form MX2 when you cross multiply the charge. The kind of ionic compound formed is MX2.

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The acid-base reaction of CH₃COOH (acid) with NH₃ (base) produce:

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It is possible to know Kr of the reaction by the sum of acidic dissociations of the half-reactions. That is:

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___________________________________

CH₃COOH + NH₃ ⇄ CH₃COO⁻ +  NH₄⁺ Kr =  1.8x10⁻⁵×1.8x10⁹ = <em>3.2x10⁴</em>

<em> </em>

As Kr is defined as:

Kr =  [CH₃COO⁻] [NH₄⁺] / [CH₃COOH] [NH₃]

And Kr is > 1  

[CH₃COO⁻] [NH₄⁺] > [CH₃COOH] [NH₃],

showing <em>products are favored</em>.

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