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Sunny_sXe [5.5K]
2 years ago
6

what's the answer! Consider having a personal loan that spans 5 years. The loan was only taken out for $6000, but the interest r

ate was a higher fixed percentage of 5.99%. How much interest will you have paid after it is paid off?
Mathematics
1 answer:
DIA [1.3K]2 years ago
7 0
^^^this answer is correct I checked
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Solve for x<br><br> 3x - 4 = 2x - 10<br><br> x = 14<br> x = 6<br> x = -6<br> x = -14
const2013 [10]
X=-6 is the correct answer
8 0
3 years ago
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50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Sergio039 [100]

Answer:

sqrt41

Step-by-step explanation:

a^2+b^2=c^2

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sqrt41

8 0
2 years ago
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I am Lyosha [343]
Central angle  = 360 / 24  = 15 degrees

ARc length =  r * theta,    where theta is the angle in radians  and r = radius
                  = 15 * 15 * pi/180  
                  =  3.93 feet to nearest hundredth.

Area of sector =  area of circle / 24  = pi*15^2 / 24 =  29.45 ft^2 
6 0
3 years ago
Using the distributive property to rewrite the expression as a multiple of a sum of two numbers with no common factor, how would
LiRa [457]
Exactly how it is 21+45
3 0
3 years ago
How do you integrate arctan(x dx? i think that if you simplify the integral you get:?
Temka [501]
Integration by parts will help here. Letting u=\arctan x and \mathrm dv=\mathrm dx, you end up with \mathrm du=\dfrac{\mathrm dx}{1+x^2} and v=x. Now

\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du
\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx

For the remaining integral, setting y=1+x^2 gives \dfrac{\mathrm dy}2=x\,\mathrm dx, so

\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C

Putting everything together, you end up with

\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C
6 0
3 years ago
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