Answer:
Option A = 17.03 g/mol
Explanation:
Given data:
Atomic mass of nitrogen = 14.01 g/mol
Atomic mass of hydrogen = 1.008 g/mol
Molecular mass of NH₃ = ?
Solution:
Molecular mass of NH₃ = (14.01 g/mol × 1) + (1.008 g/mol × 3)
Molecular mass of NH₃ = 14.01 g/mol + 3.024 g/mol
Molecular mass of NH₃ = 17.03 g/mol
Ammonia consist of hydrogen and nitrogen both are nonmetals that's why ammonia is an covalent compound.
I don’t know ask you’re teacher
Albert Einstein's work focused on relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light.
<h3>Who is Albert Einstein?</h3>
The physicist Albert Einstein was born in Ulm Württemberg Germany in 1875. He migrated to the United States at the height of the Nazi regime in Germany where he became a professor of physics at Princeton University.
His work focused on the relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light. These ideas still remain fundamental in science today.
I became interested in the work of Albert Einstein because of the fact that is work is fundamental to the understanding of quantum mechanics and the idea of gravity. He laid the foundation upon which modern physics is built.
Learn more about Albert Einstein:brainly.com/question/2964376
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Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.
<h3>
<u>Answer</u> - 5.85g</h3>
<h3>
<u>Solution</u> - </h3>
Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):
Given,
Molar mass of NaCl, M = 58.5g/mol
Volume of the solution, V= 100ml = 0.1L
Molarity, S= 1M
Mass of the solute,W=?
W=SMV
= 1×58.5×0.1
= 5.85g
