Answer:
He means Explain the differences between mix and match. Give one example of each.
Explanation:
Answer:Chemical reaction
Explanation:
The main concept that must be applied to determine the coefficients (amount of each item) is that there must be equal amounts of each element on each side of the equation. We are not destroying or creating new atoms. In this case, the unbalanced reaction formula is:
B
r
2
+
K
I
=
K
B
r
+
I
2
There are a two problems we need to solve before it will be balanced:
There are two moles of Iodine atoms (
I
) on the right side of the equation, while there is only one mole on the right side.
There are two moles of bromine (
B
r
) atoms on the left side, while there is only one on the right.
Since there are two moles of bromine atoms on the left side, we need two moles on the right as well. We can do this by adding a coefficient of two to the
'
K
B
r
'
term in the equation. Our now modified equation looks like this:
B
r
2
+
K
I
=
2
K
B
r
+
I
2
There is one mole of Iodine atoms on the left, and two on the right. To fix this, we add a coefficient of two to the
'
K
I
'
term. The resulting equation is below.
B
r
2
+
2
K
I
=
2
K
B
r
+
I
2
Bonus step: We can also put ones in front of the coefficient-less species. This is like changing a phrase from "an apple" to "1 apple". It is the exact same thing, but makes it a little more clear sometimes. This would like like this:
1
B
r
2
+
2
K
I
=
2
K
B
r
+
1
I
2
Can you see that there is now an equal amount of each element on each side of the equation? That means that it is balanced.
Answer : The volume of water added are, 15 mL
Explanation :
Formula used :
where,
are the initial molarity and volume of HCl.
are the final molarity and volume of water.
We are given:
Putting values in above equation, we get:
Hence, the volume of water added are, 15 mL
Answer:
29.75 Kg of NH₃
Solution:
In order to calculate the theoretical yield, first we will identify the limiting reactant.
According to equation,
6 g (3 moles) H₂ requires = 28 g (1 mole) N₂
So,
5250 g H₂ will require = X g of N₂
Solving for X,
X = (5250 g × 28 g) ÷ 6 g
X = 25433 g of N₂
Hence, it is found that H₂ is the limiting reactant because N₂ is provided in excess (32700 g). Therefore,
As,
6 g (3 mole) H₂ produced = 34 g ( 2 moles) of NH₃
So,
5250 g H₂ will produce = X g of NH₃
Solving for X,
X = (5250 g × 34 g) ÷ 6 g
X = 29750 g of NH₃
Or,
X = 29.75 Kg of NH₃
A element mixture (key word: mixture) due to the mixture containing 2 different types of elements it can be said that it’s highly likely that the mixture was not a compound but instead of a mixture due to mixture meaning more than 1 material. Hopes this help!
