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3 years ago

Solve for x and graph: show your work! -9x -30 < 15?

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

-9x - 30 < 15
 + 30 + 30
 -9x < 45
 -9 -9
 x < -5

devlian [24]3 years ago

4 0

First you want to isolate X by adding 30 to both sides.
-9x < 45
Then divide both sides by -9.
x < -5
Graph that by drawing a vertical line at x = -5 and shading in everything to the left.

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aliya0001 [1]

Answer:

Step-by-step explanation:

5 red

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altogether the is 30 marbles so that means it is 'out of' 30

and because the is 5 red it would be 5/30

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that should be the answer but if you have to work the total all together then it would be 15/30

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3 years ago

If the leg of a triangle is 48 and the hypotenuse is 60 what is the length of the other leg

AURORKA [14]

Answer:

The length of the other would be 36.

Step-by-step explanation:

a² + b² = c²

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b² = 60² - 48²

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2 years ago

Answer Question number 5 Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$

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3 years ago

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DaniilM [7]

Answer:

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Step-by-step explanation:

3^-3 can be written as 1/3^3 and 3^3 = 3x3x3= 27

Therefore, the answer is 1/27.

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