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Reptile [31]
3 years ago
11

Solve for x and graph: show your work! -9x -30 < 15?

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
-9x - 30 < 15
<u>      + 30 + 30</u>
       <u>-9x</u> < <u>45</u>
        -9     -9
           x < -5
devlian [24]3 years ago
4 0
First you want to isolate X by adding 30 to both sides.
-9x < 45
Then divide both sides by -9.
x < -5
Graph that by drawing a vertical line at x = -5 and shading in everything to the left.
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Is the following number rational or irrational? Choose the appropriate reason. PA N. 1.4 7+ V5 Rational, because it is the sum o
sveticcg [70]

Answer:

u need to give more points for thouse kind of questions

Step-by-step explanation:

3 0
3 years ago
A circle is centered at the point (5,-4) And passes through the point (-3,2). What is the equation of the circle?
Natalka [10]
The equation of a circle is:

(x-h)2 + (y-k)2 = r2

where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:

(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2

So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):

r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2

r= 10

The final equation is:

(x-5)2 + (y+4)2 = 102
8 0
3 years ago
Sec^6x(secxtanx)-sec^4(secxtanx)=sec^5xtan^3x<br> Verify the trigonometric identity
mario62 [17]

I guess you mean

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan^3x

On the left side, we have a common factor of \sec^4x(\sec x\tan x)=\sec^5x\tan x, so that

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan x(\sec^2x-1)

Recall that

\sec^2x=1+\tan^2x

from which it follows that

\sec^5x\tan x(\sec^2x-1)=\sec^5x\tan x\tan^2x=\sec^5x\tan^3x

7 0
3 years ago
4²(4²)<br> 2. 5⁴(5)÷2¹ <br> 3. (5+3)²<br> Solve the following expressions
omeli [17]
  1. 4^2*4^2
  2. 4^4
  3. 256

  1. 5^4(5)/2^1
  2. 625*5/2^1
  3. 625*5/2
  4. 625*5/2
  5. 3125/2

  1. (5+3)^2
  2. 8^2
  3. 64

Hope this helps, have a BLESSED and wonderful day! :-)

3 0
2 years ago
Help Me Plz!!!!!! THX!!!!!!!!!!
Sauron [17]

\sqrt{5} is irrational

A rational number can be expressed in the form

\frac{a}{b} where a, b ∈ Z ( integers )

\frac{-9}{5} is in this form → rational

\sqrt{5} cannot be expressed in this form → irrational

\frac{7}{3} is in this form → rational

\sqrt{9} = ± 3 and \frac{3}{1}, - \frac{3}{1} → rational






3 0
3 years ago
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