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3 years ago

Propose 4 reasons why society should support scientific research (use an example to support each of your reasons).

Physics

1 answer:

Andrei [34K]3 years ago

4 0

Answer:

Scientific research can promote the raise of the productivity of the society.Which means it can help people produce more goods in a much shorter time and better quality.

From the perspective of a country, if scientific research will not be supported, that country will face a highly pressure and threaten from other counties due to the technology advancement.Technology development will largely determine the military and economic power of a country.

From personally view,our next generation need to be good educated with support.A large part of the area will focus on scientific research,so if we want our children to perform better than us and create a better future.We need to support the scientific research.Nowadays, the AI technology is a very good example that society should support the scientific research. In the long run, we not only benefit from the progress and facility,but we can harvest from the investment into the AI scientific research.

Not the least,scientific research will help human being to know the unknown things in the society,that deep understanding will contribute ourselves to get better way to get along with the new environment and new world.

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The insulating solid sphere in the previous Example 24.5 has the same total charge Q and radius a as the thin shell in the examp

BaLLatris [955]

Answer and Explanation:

Using Gauss's law,

If r>a

then charge enclosed in all the three cases is same as Q.

So Electric field for all three is same.

So {1,1,1}.

(b) r<a,

Charge enclosed in case of shell is zero since all charge is present on the surface. So E = 0.

Charge enclosed by incase of point charge is Q.

Charge enclosed in case of sphere is Qr3/a3 which is less than Q.

So ranking {2,3,1}

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4 years ago

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Oksanka [162]

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4 years ago

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4 years ago

Read 2 more answers

A very slippery ice cube slides in a vertical plane around the inside of a smooth, 20-cm-diameter horizontal pipe. The ice cube’

weeeeeb [17]

Answer:

Explanation:

Given that,

Diameter of pipe

d = 20cm

Then, radius =d/2 =20/2

r = 10cm =0.1m

The speed at the bottom is

Vi = 3m/s

Speed at the top Vf?

At the bottom the cube is at a height of 0m

Then, y1 = 0m

At the top the cube is at a height which is the same as the diameter of the pipe

y2 = 0.2m

Now, let us consider, the energy conservation equation , which is the sum of kinetic energy and gravitational potential energy, given by,

K2 + U2 = K1 + U1

½m•Vf² + m•g•y2 = ½m•Vi² + m•g•y1

Divide all through by m

½•Vf² + g•y2 = ½•Vi² + g•y1

Since y1 = 0

So we have,

½•Vf² + g•y2 = ½•Vi²

½•Vf² = ½•Vi² — g•y2

Multiply through by 2

Vf² = Vi² —2g•y2

Vf = √(Vi²—2g•y2)

g is a constant =9.81m/s2

Vf = √(3²—2×9.81×0.2)

Vf = √(9—0.981)

Vf = √8.019

Vf = 2.83m/s

The speed of the ice cubes at the top of the pipe is 2.83m/s

7 0

3 years ago

A car accelerates uniformly from rest to 16.4 m/s in 4.35 s along a level stretch of road. Ignoring friction, determine the aver

Pachacha [2.7K]

Answer:

(a) Average power required to accelerate is 2.87 x 10⁴ W

(b) Average power is required to accelerate is 6.25 x 10⁴ W

Explanation:

Given :

Initial speed of car, u = 0 m/s

Final speed of the car, v = 16.4 m/s

Time, t = 4.35

Initial kinetic energy of car, K₁ = 0

Final kinetic energy of car, K₂ = (mv²)/2

Here m is the mass of the car.

Applying Work-Energy theorem,

Work done = Change in kinetic energy

W = ΔK ....(1)

Power is defined as work done per unit time. So,

P = W/t

From equation (1), the above equation becomes:

P = ΔK/t

P = (K₂ - K₁)/t

P = (mv²)/(2t) .....(2)

(a) Weight of the car, W = 9.11 x 10³ N

But, W = m x g

Here g is acceleration due to gravity.

So, m = W/g

Thus, the equation (2) becomes:

$P=\frac{Wv^{2} }{2gt}$ ....(3)

Substitute the suitable values in the above equation.

$P=\frac{9.11\times10^{3}\times (16.4)^{2} }{2\times9.8\times4.35}$

P = 2.87 x 10⁴ W

(b) Weight of the car, W = 1.98 x 10⁴ N

Substitute this value of W in equation (3) with other suitable values.

$P=\frac{1.98\times10^{4}\times (16.4)^{2} }{2\times9.8\times4.35}$

P = 6.25 x 10⁴ W

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3 years ago