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2 years ago

Write the standard equation of the circle in the graph.

Mathematics

1 answer:

stellarik [79]2 years ago

8 0

Answer:

$(x-4)^2 + (y+3)^2 = 16$

Step-by-step explanation:

$(x-h)^2 + (y-k)^2 = r^2$

where $(h, k)$ is the center of the circle and $r$ is the radius

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Plz help I’m getting timed

Fed [463]

id say its a rhombus. all the other shapes can have right angles

6 0

3 years ago

Read 2 more answers

Evaluate x - 7 for x = 14.

Aleksandr-060686 [28]

Answer:

x=21

Step-by-step explanation:

x-7=14

add 7 to both sides

x=21

8 0

3 years ago

I need help with this, neither of my parents can help me and i want to understand.

olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

$(4^{\frac{2}{5}})^{\frac{1}{4}},$

use exponents property

$(a^m)^n=a^{m\cdot n}$

So,

$(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}$

2. Why $10^{\frac{1}{3}}=\sqrt[3]{10}?$

Raise both sides to 10 power:

$(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10$

So,

$(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3$

3. Simplify $\dfrac{3^4}{9}$

Use the Quotient of Powers Property:

$\dfrac{a^m}{a^n}=a^{m-n}$

Then

$\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2$

4. Solve $4\sqrt{2}+5\sqrt{4}$

First, note that $\sqrt{4}=2,$ then

$4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10$

Number $4\sqrt{2}$ is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.

5. The same as option 4.

3 0

2 years ago

Find the standard form.

Deffense [45]

Answer:

Step-by-step explanation:

Lets break this down piece by piece.

So first, add 500,000 and 30,000. that would be 530,000.

Next, add on 5,000, which is 535,000

After that, add 300. ( 535,300. )

Then add up 50 and 3 which is 53.

Lastly, your answer is 535,353.

4 0

3 years ago

If -7(u-3)=-14 what is the value of y

Mnenie [13.5K]

Step-by-step explanation:

I have answered ur question

7 0

3 years ago