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inysia [295]
3 years ago
7

What is the slope of the line? 7 1 T 1 2 4 -le 0 1 0 -

Mathematics
2 answers:
Helga [31]3 years ago
6 0

Answer:

1/2

Step-by-step explanation:

(-2,-1)(2,1)

m = 1-(-1) / 2-(-2)

m = 2/4 or 1/2

FinnZ [79.3K]3 years ago
4 0

Answer:

please add me on sñap

Step-by-step explanation:

arshad2623f

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3 years ago
What is the range of y = sin-1x? [–1, 1] [0, π] left-bracket negative startfraction pi over 2 endfraction, startfraction pi over
soldi70 [24.7K]

The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

<h3>What is the range of the function?</h3>

Range of a function is the set of all the possible output values which are valid for that function.

The trigonometry function given in the problem is,

y = \sin^{-1}x

The above function can be written as,

\sin y = x

The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.

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This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,

-\dfrac{\pi}{2}\leq x\leq\dfrac{\pi}{2}

Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

Learn more about the range of the function here;

brainly.com/question/2264373

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Step-by-step explanation:

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