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2 years ago

HELPPP PLZ ASAP I WILL MARK U AS A BRAINLIEST

Mathematics

1 answer:

Umnica [9.8K]2 years ago

3 0

Answer:

-7

Step-by-step explanation:

2-3(3)=-7

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What does the variable X equal

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The variable x always equals 1

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Suppose that $f(x)$ and $g(x)$ are functions on $\mathbb{r}$ such that the range of $f$ is $[-5,3]$, and the range of $g$ is $[-

grigory [225]

The largest possible value of b is 10, since for some x = x₀ it could be the case that f(x₀) = -5 and g(x₀) = -2; then f(x₀) g(x₀) = -5 × -2 = 10.

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2 years ago

Question 1

777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

$n = 6 + 4p$

In which p is the current position.

How many tiles would there be in position 22?

This is n when $p = 22$ . So

$n = 6 + 4*22 = 6 + 88 = 94$

There would be 94 tiles.

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2 years ago

After the movie premiere 99 out of 130 people surveyed said they liked the movie. What is the experimental probability that the

Margaret [11]

Out of the 130 people surveyed, 99 people said they liked the movie. So to figure out the probability that the next person likes the movie, you divide 99 from 130.
The answer is approximately 76%.

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3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago