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vredina [299]
3 years ago
10

Exit a spinner used for a game is divided into 3 sections: yellow, green, and orange. janie spins the spinner 20 times. the spin

ner lands on green 8 times. what is the experimental probability that the spinner does not land on green?
Mathematics
2 answers:
Eva8 [605]3 years ago
7 0
Experimental probability it lands on the green is 8/20 = 2/5

Exp. probability it does not land on green is 1 - 2/5 = 3/5   or 60%.
Rina8888 [55]3 years ago
5 0

Answer:

3/5

Step-by-step explanation:

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Can someone plzzz help with numbers 11-12 plzzz show work cuz I’m not understanding this plz
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11-12=-1

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5 0
3 years ago
Simplify 13 over the quantity of negative 3 plus 2i.
QveST [7]

13

−

3

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2

i

Multiply by

−

3

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3

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13

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3

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13

(

−

3

−

2

i

)

(

−

3

+

2

i

)

(

−

3

−

2

i

)

Expand

(

−

3

+

2

i

)

(

−

3

−

2

i

)

using the FOIL Method.

Tap for more steps...

13

(

−

3

−

2

i

)

−

3

⋅

−

3

−

3

(

−

2

i

)

+

2

i

⋅

−

3

+

2

i

(

−

2

i

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13

(

−

3

−

2

i

)

9

−

4

i

2

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13

(

−

3

−

2

i

)

9

+

4

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−

3

−

2

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7 0
3 years ago
Find the critical value necessary to form a confidence interval at the level of confidence shown below.
Rzqust [24]

Answer:

the critical value for 0.87 level of confidence is 1.51

Step-by-step explanation:

Given the data in the question;

level of confidence = 0.87

now,

1 - c = 0.87

c = 1 - 0.87

c = 0.13

c/2 = 0.13/2 = 0.065

now

1 - c/2  = 1 - 0.065 = 0.935

so our level of significance ∝ = 0.935

Now, the critical value will be;

Z_{0.935 is obtained as follows;

P( Z < z ) = 0.935

so we find the value from ( standard normal distribution table )

P( Z < 1.51 ) = 0.935

Therefore, the critical value for 0.87 level of confidence is 1.51

8 0
3 years ago
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