2. What are the solutions to 16x2 - 12x = 54? Select all that apply.

Rina draws a plan of her school on a coordinate grid. She plots the school gate at point p(-8,-1) and the library at point Q(2,5

natka813 [3]

Answer:

The coordinates of the science lab is:

x = -14/3 , y = 1

Step-by-step explanation:

∵ P is (-8 , -1) and Q is (2 , 5)

∵ The point of the science lab is (x , y)

∵ The science lab point divided PQ at ratio 2 : 1 from Q (two thirds PQ)

∴ $x=\frac{m_{1}x_{p}+m_{2}x_{q}}{m_{1}+m_{2}}$

∴ $y=\frac{m_{1}y_{p}+m_{2}y_{q}}{m_{1}+m_{2}}$

∴ $x=\frac{2(-8)+1(2)}{1+2}=\frac{-14}{3}$

∴ $y=\frac{2(-1)+1(5)}{2+1}=\frac{3}{3}=1$

∴ The point of science lab = (-14/3 , 1)

5 0

3 years ago

Sophie Ruth is eating 50% gram chocolate which contains 30% cocoa how many grams of cocoa are in the chocolate bar

Gnoma [55]

There’s 15 grams
Hope this helps!

4 0

3 years ago

Read 2 more answers

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

4 years ago

FAST PLEASE‼️‼️‼️ VERY EASY‼️‼️‼️

Ymorist [56]

These are really easy and it’s worth the points

7 0

4 years ago

How to find the diameter of a circle when given the circumference?

andre [41]

The formula for the circumference of a circle, c=πd or c=2πr, can also be used to find the diameter or radius of a circle.

Let's look at an example.

A circle has a circumference of 20.72 m. What is its diameter?

First, write down the formula.

c=πd

Next, fill in the values that you know.

20.72 m=3.14 d

Then, divide both sides of the equation by 3.14

6.6=d

The answer is the diameter is 6.6 meters.

5 0

3 years ago