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Elena-2011 [213]

3 years ago

11

Name an outcome that has a probability between 0.5 and 1

2 answers:

diamong [38]3 years ago

8 0

Answer:

0.6

Step-by-step explanation:

sergey [27]3 years ago

6 0

Answer:

a coin flip

Step-by-step explanation:

The probability of an event is a number describing the chance that the event will happen. An event that is certain to happen has a probability of 1. An event that cannot possibly happen has a probability of zero.

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Can some one just show me how to do it? & ill find the answer

svetlana [45]

Assuming you're going off of current data, 6.2% of gross pay is taken out for the Social Security tax.
So, simply take the gross pay 2344/100, which equals 23.44, then multiply by the percentage,6.2, to get 145.32

So, $145.32 is deducted from your gross pay.

There. Now you don't even need to find the answer.

4 0

3 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

adell [148]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

8 0

2 years ago

Read 2 more answers

COULD SOMEONE PLEASE HELP ME WITH THIS IT'S REALLY IMPORTANT-

san4es73 [151]

Answer:

b i think

Step-by-step explanation:

5 0

2 years ago

Use the formula to find the standard error of the distribution of differences in sample means, x¯1-x¯2 . Samples of size 110 fro

Volgvan

Answer:

2.104

Step-by-step explanation:

Data provided in the question:

For sample 1,

n₁ = 110

μ₁ = 94

s₁ = 14

For sample 2,

n₂ = 85

μ₂ = 72

s₂ = 15

Now,

Standard error = $\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

or

Standard error = $\sqrt{\frac{14^2}{110}+\frac{15^2}{85}}$

or

Standard error = √4.43

or

Standard error = 2.104

7 0

2 years ago

Basic Algebra. Can you help me please?????

poizon [28]

Answer:

does BD bisect angle EBC?

5 0

2 years ago

Read 2 more answers