Answer:
Explanation:
Here, we want to calculate the number of moles of methane in the container
From the ideal gas law:
where:
P is the pressure inside the container which is 3 atm
V is the volume of the container which is 2 L
R is the molar gas constant which is 0.0821 Latm/mol.k
T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)
n is the number of moles that we want to calculate
Substituting the values, we have it that:
Colligative properties are properties of solutions that result from adding solute to a solvent and that depend on the concentration of solute particles, but independent of the identity of the solute molecules or ions. The four colligative properties are boiling point elevation, freezing point depression, osmotic pressure, and vapor pressure lowering.
Answer:
Answer is in the explanation.
Explanation:
For the reaction:
Ba₃(PO₄)₂(aq) + 3Na₂SO₄(aq) → 3BaSO₄(s) + 2Na₃PO₄(aq)
As Na₂SO₄(aq) is in excess, limiting reactant is Ba₃(PO₄)₂(aq). As the molarity of the solution is 0,25M and you knew the volume of the solution, you can obtain the moles of Ba₃(PO₄)₂ doing 0,25M×volume.
As 1 mol of Ba₃(PO₄)₂(aq) react with 3 moles of BaSO₄ the moles of BaSO₄ are three times moles of Ba₃(PO₄)₂.
As BaSO₄ molar mass is 233,38g/mol. The mass of BaSO₄ is given by moles of BaSO₄ × 233,38g/mol
I hope it helps!
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