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poizon [28]
3 years ago
9

How do I do question number 4?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
6 0
I hope you understood
hit me up if you have any other questions :>

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Which of the following tool components is unlikely to present a hazard
nydimaria [60]

Gloves is the tool component which will unlikely present a hazard in this scenario.

<h3>What is Hazard?</h3>

This is referred to as potential source of harm when performing various types of activities.

Gloves will unlikely cause harm as it is used to prevent the risk of electric shock when handling electrical devices which is why it is the most appropriate choice.

Read more about Hazard here brainly.com/question/7310653

#SPJ1

6 0
2 years ago
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
2 years ago
Copper2 nitrate &gt; nitrogen dioxide + copper2 oxide+ oxygen
erastovalidia [21]
Cu(NO3)2>NO2+CuO+O2 balanced: 2Cu(NO3)2=4NO2+2CuO+O2
3 0
3 years ago
How much heat energy is required to raise the temperature of 15g of silver from 25°C to 55°C, assuming the specific heat of silv
Alenkasestr [34]

Answer:

108 j

Explanation:

.24 j/g-C  * 15 g * (55-25) =

6 0
2 years ago
Calcium chlorate has the formula Ca(ClO3)2. Which best describes the structure of calcium chlorate? One molecule of calcium chlo
deff fn [24]
The formula Ca(ClO3)2 breaks down to: 1 calcium atom, 2 chlorine atoms, and 6 oxygen atoms. Therefore:

One molecule of calcium chlorate contains 9 atoms [correct]

Calcium chlorate is not an element, nor does the molecule contain only 3 atoms [incorrect]

It does not take 9 different elements - just the three elements we listed [incorrect]

Calcium chloride only contains one Ca group [incorrect]


6 0
3 years ago
Read 2 more answers
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