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Alexandra [31]
3 years ago
15

How to predict boiling points?

Chemistry
2 answers:
JulijaS [17]3 years ago
5 0
At 212F, water begins to boil... You can try using a thermometer, but your best bet while cooking is you look for the tiny little air bubbles, like ultra small bubbles all on the bottom... 
Alenkinab [10]3 years ago
4 0
When the water starts boiling out with bubbles...
You might be interested in
How many grams of O2 are needed to react with 8.15 g of C2H2?
xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

  • C₂H₂: 2 moles
  • O₂: 5 moles
  • CO₂: 4 moles
  • H₂O: 2 moles

The molar mass of each compound is:

  • C₂H₂: 26 g/mole
  • O₂: 32 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₂H₂: 2 moles* 26 g/mole= 52 g
  • O₂: 5 moles* 32 g/mole= 160 g
  • CO₂: 4 moles* 44 g/mole= 176 g
  • H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2}  }{52 grams of C_{2} H_{2}}

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

8 0
3 years ago
What word is used to refer to a group of organ systems working together?
kotegsom [21]

Answer:

1

Explanation:

in my opinion,The answer would be organism

please mark me as brainliest

6 0
3 years ago
Please ignore my answers because they are wrong.
earnstyle [38]

Answer:

The wavelength of the radio wave is 3.003 m.

The energy of the radio wave is 6.6194\times 10^{-26} J.

Explanation:

Frequency of the radio waves, ν = 99.9 MHz = 99.9\times 10^6 Hz

Wavelength and frequency are related to each other by realtion:

\lambda =\frac{c}{\nu }

\lambda = Wavelength of the wave

c = speed of the light

ν = Frequency of the wave

\lambda =\frac{3\times 10^8 m/s}{99.9\times 10^6 s^{-1}}=3.003 m

The wavelength of the radio wave is 3.003 m.

The energy of the electromagnetic wave is given by Planck's equation:

E=h\times \nu

h = Planck's constant = 6.626\times 10^{-34} Js

The energy of the radio wave with 99.9 MHz frequency will be:

E=6.626\times 10^{-34} Js\times 99.9\times 10^6 s^{-1}

E = 6.6194\times 10^{-26} J

The energy of the radio wave is 6.6194\times 10^{-26} J.

4 0
3 years ago
Describe the nature and variety of instruments used to detect radiation.
pickupchik [31]
A variety of handheld and laboratoryinstruments is available for detectingand measuring radiation. ... Geiger Counter, with Geiger-Mueller (GM) Tube or Probe—A GM tube is a gas-filled device that, when a high voltage is applied, creates an electrical pulse when radiation interacts with the wall or gas in the tube.
3 0
3 years ago
Read 2 more answers
The picture below shows a sample from a tree.<br> What kind of tree is this?
HACTEHA [7]

Answer:

I believe it is Spruce, because of the shape of the leaves

7 0
3 years ago
Read 2 more answers
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