Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

92% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Answer:
Lower quartile 3, median 5, Upper quartile 7
Step-by-step explanation:
First divide the data in half 1 3 4 and 6 7 7
The median is the middle between 4 and 6, so it is 5.
The lower quartile is the median in the lower half, 3
The upper quartile is the median in the upper half, 7